Answer:
(ab+10+a)-(6ab×6ab-2ab+8)
=ab+10+a-6ab×6ab+ab-8
=ab+10+a-36a²b²+2ab-8
=36a²b²+(ab-2ab)+a+(10-8)
therefore the answer is 36a²b²+3b+a+2
Answer:
The answer is "eccentricity = 0.5 and distance = 60".
Step-by-step explanation:
Given value:
![\bold{r=\frac{420}{ -14 +7 \sin \theta}}](https://tex.z-dn.net/?f=%5Cbold%7Br%3D%5Cfrac%7B420%7D%7B%20-14%20%2B7%20%5Csin%20%5Ctheta%7D%7D)
Standard equation formula:
![\bold{\to r=\frac{ep}{1- e \sin \theta}}](https://tex.z-dn.net/?f=%5Cbold%7B%5Cto%20r%3D%5Cfrac%7Bep%7D%7B1-%20e%20%5Csin%20%5Ctheta%7D%7D)
![\to r=\frac{\frac{420}{-14}}{1- \frac{7}{14} \sin \theta}\\\\\to r=\frac{ -30 }{1- \frac{1}{2} \sin \theta}\\\\\to r=\frac{ -30 }{1- 0.5 \sin \theta}\\\\](https://tex.z-dn.net/?f=%5Cto%20r%3D%5Cfrac%7B%5Cfrac%7B420%7D%7B-14%7D%7D%7B1-%20%5Cfrac%7B7%7D%7B14%7D%20%5Csin%20%5Ctheta%7D%5C%5C%5C%5C%5Cto%20r%3D%5Cfrac%7B%20-30%20%7D%7B1-%20%5Cfrac%7B1%7D%7B2%7D%20%5Csin%20%5Ctheta%7D%5C%5C%5C%5C%5Cto%20r%3D%5Cfrac%7B%20-30%20%7D%7B1-%20%200.5%20%5Csin%20%5Ctheta%7D%5C%5C%5C%5C)
![\boxed{ r=\frac{-30 }{1- 0.5 \sin \theta}}](https://tex.z-dn.net/?f=%5Cboxed%7B%20r%3D%5Cfrac%7B-30%20%7D%7B1-%200.5%20%5Csin%20%5Ctheta%7D%7D)
compare the above value with the Standard equation:
![\to e=0.5 \\ \to ep= -30\\](https://tex.z-dn.net/?f=%5Cto%20e%3D0.5%20%5C%5C%20%20%5Cto%20ep%3D%20-30%5C%5C)
calculating the value of p:
![\to 0.5 p= -30\\\\\to p= \frac{-30}{0.5}\\\\\to p= \frac{-300}{5}\\\\\to p= - 60](https://tex.z-dn.net/?f=%5Cto%200.5%20p%3D%20-30%5C%5C%5C%5C%5Cto%20p%3D%20%5Cfrac%7B-30%7D%7B0.5%7D%5C%5C%5C%5C%5Cto%20p%3D%20%5Cfrac%7B-300%7D%7B5%7D%5C%5C%5C%5C%5Cto%20p%3D%20-%2060)
eccentricity (e) = 0.5
distance = - 60
distance |d| = 60
Answer:
y =
x
Step-by-step explanation:
The equation of a line passing through the origin (0, 0 ) is
y = mx ( where m is the slope )
m =
=
, thus
y =
x
Answer:
b and e.
Step-by-step explanation:
You will find this by solving each equation for 15b (get 15b by itself)
50.27yd²
Using the formulasA<span>=</span><span>π</span><span>rto the second power</span>d<span>=</span><span>2</span><span>r</span>Solving forAA=14πd2=14·π·82≈50.26548yd²