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3 years ago

How do free radicals from carcinogens affect dna in cells?

Physics

1 answer:

puteri [66]3 years ago

7 0

Answer:

By definition, free radicals are any molecular specie capable of independent existence that contains an unpaired electron in an atomic orbital.

Explanation: Free radicals are highly reactive species, capable in the nucleus and in the membrane of cells of damaging biologically relevant molecules such as DNA, proteins, carbohydrates, and lipids.

Mutagenesis through oxidative DNA damage is a frequent event in a normal human cell. Oxygen Free Radicals (OFR) plays an important role in the expansion of tumor clones. OFR attack the deoxyribosyl backbone of DNA. Endogenous DNA lesions are genotoxic and induce mutations. This lesions are relatively formed and is mutagenic, therefore, a potential biomaker of carcenogenesis.

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A runner starts from rest and accelerates uniformly to a speed of 8.0 meters per second in 4.0 seconds. the magnitude of the acc

Paha777 [63]

The magnitude of the acceleration of the runner is given by:
$a= \frac{v_f-v_i}{t}$
where
$v_f=8.0 m/s$ is the final speed of the runner
$v_i=0$ is the initial speed of the runner
$t=4.0 s$ is the time taken

By substituting data into the equation, we find the magnitude of the acceleration:
$a= \frac{8.0 m/s -0}{4.0 s}=2 m/s^2$

7 0

4 years ago

How do uplift and erosion help to form a batholith?

saul85 [17]

<span>the correct answer would be <u>by exposing a large body of igneous rock to the surface

</u></span>

6 0

3 years ago

Read 2 more answers

At t1 = 2.00 s, the acceleration of a particle in counterclockwise circular motion is 6.00 i + 4.00 j m/s2 . It moves at constan

Jet001 [13]

The particle moves with constant speed in a circular path, so its acceleration vector always points toward the circle's center.

At time $t_1$ , the acceleration vector has direction $\theta_1$ such that

$\tan\theta_1=\dfrac{4.00}{6.00}\implies\theta_1=33.7^\circ$

which indicates the particle is situated at a point on the lower left half of the circle, while at time $t_2$ the acceleration has direction $\theta_2$ such that

$\tan\theta_2=\dfrac{-6.00}{4.00}\implies\theta_2=-56.3^\circ$

which indicates the particle lies on the upper left half of the circle.

Notice that $\theta_1-\theta_2=90^\circ$ . That is, the measure of the major arc between the particle's positions at $t_1$ and $t_2$ is 270 degrees, which means that $t_2-t_1$ is the time it takes for the particle to traverse 3/4 of the circular path, or 3/4 its period.

Recall that

$\|\vec a_{\rm rad}\|=\dfrac{4\pi^2R}{T^2}$

where $R$ is the radius of the circle and $T$ is the period. We have

$t_2-t_1=(5.00-2.00)\,\mathrm s=3.00\,\mathrm s\implies T=\dfrac{3.00\,\rm s}{\frac34}=4.00\,\mathrm s$

and the magnitude of the particle's acceleration toward the center of the circle is

$\|\vec a_{\rm rad}\|=\sqrt{\left(6.00\dfrac{\rm m}{\mathrm s^2}\right)^2+\left(4.00\dfrac{\rm m}{\mathrm s^2}\right)^2}=7.21\dfrac{\rm m}{\mathrm s^2}$

So we find that the path has a radius $R$ of

$7.21\dfrac{\rm m}{\mathrm s^2}=\dfrac{4\pi^2R}{(4.00\,\mathrm s)^2}\implies\boxed{R=2.92\,\mathrm m}$

8 0

3 years ago

A circuit has an impedance of 5 ohms and a voltage of 100 volts. What is the current flow?

Ket [755]

A circuit with an impedance of 5 ohms and a voltage of 100 volts has a current flow of 20 A.

The expression of an electronic component, circuit, or system's resistance to alternating and/or direct electric current is called impedance, indicated by the letter Z. Resistance and reactance are two distinct scalar (one-dimensional) phenomena that combine to form impedance, a vector (two-dimensional) variable.

$Z^{}$ = $\frac{V}{I}$

(for a pure resistor where Z=R,preserving the form of the DC Ohm's law).

$I=\frac{V}{Z}$

$I = \frac{100}{5}$

I = 20 A

Therefore, A circuit with an impedance of 5 ohms and a voltage of 100 volts has a current flow of 20 A.

Learn more about impedance here;

brainly.com/question/2263607

#SPJ4

6 0

2 years ago

A bullet with a mass ????b=13.5 g is fired into a block of wood at velocity ????b=249. The block is attached to a spring that ha

larisa86 [58]

Answer:

$M = 0.436 kg$

Explanation:

As per energy conservation we can say that energy stored in the spring at the position of maximum compression must be equal to the kinetic energy of bullet and block system

so here we have

$\frac{1}{2}(m + M)v^2 = \frac{1}{2} kx^2$