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3 years ago

Summarize how the force of gravity factors into at least three processes in the formation of stars.

Physics

1 answer:

nika2105 [10]3 years ago

8 0

It pulls them together

It compressed them

It makes the materials together

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A 1250-kg compact car is moving with velocity v1 =36.2i^+12.7j^m/s. It skids on a frictionless icy patch and collides with a 448

MA_775_DIABLO [31]

Momentum is conserved, so the sum of the separate momenta of the car and wagon is equal to the momentum of the combined system:

(1250 kg) ((36.2 i + 12.7 j ) m/s) + (448 kg) ((13.8 i + 10.2 j ) m/s) = ((1250 + 448) kg) v

where v is the velocity of the system. Solve for v :

v = ((1250 kg) ((36.2 i + 12.7 j ) m/s) + (448 kg) ((13.8 i + 10.2 j ) m/s)) / (1698 kg)

v ≈ (30.3 i + 12.0 j ) m/s

7 0

3 years ago

A 10-g bullet moving horizontally with a speed of 1.8 km/s strikes and passes through a 5.0-kg block initially at rest on a hori

UNO [17]

Answer:

6.4 J

Explanation:

m = mass of the bullet = 10 g = 0.010 kg

v = initial velocity of bullet before collision = 1.8 km/s = 1800 m/s

v' = final velocity of the bullet after collision = 1 km/s = 1000 m/s

M = mass of the block = 5 kg

V = initial velocity of block before collision = 0 m/s

V' = final velocity of the block after collision = ?

Using conservation of momentum

mv + MV = mv' + MV'

(0.010) (1800) + (5) (0) = (0.010) (1000) + (5) V'

V' = 1.6 m/s

Kinetic energy of the block after the collision is given as

KE = (0.5) M V'²

KE = (0.5) (5) (1.6)²

KE = 6.4 J

4 0

4 years ago

A girl walks 5 blocks east and then two blocks north. Find her total displacement.

Vlad [161]

Her displacement would be -3 blocks

displacement = final position - initial position

4 0

3 years ago

A mass is oscillating horizontally on a spring. At the locations A, B, C, D, and E, photogates are used to measure the speed of

svetoff [14.1K]

Complete Question

The complete question is is shown on the first uploaded

Answer:

The elastic potential energy at point B is $PE_{elastic} = 50J$

The kinetic energy at point D is $KE = 75J$

Explanation:

Looking at the given point we can observe that mechanically energy(i.e potential and kinetic energy ) is conserved and it value is $E_ {m} = 100J$

So at point B

$E_{m} = PE_{elastic} +KE$

$100 = PE_{elastic} + KE$

KE at point B is 50J

So $PE_{elastic} = 100 - 50 = 50J$

Now at point D

$E_{m} = PE_{elastic} +KE$

$PE_{elastic}$ at point D is 25J

So $KE = 100 - 25 = 75J$

4 0

3 years ago

Un barco va a una velocidad de 45 ml/h, luego el capitán ordena acelerar hasta que la velocidad hasta que la velocidad sea de 60

Sophie [7]

Pregunta completa:

Un barco va a una velocidad de 45 ml/h, luego el capitán ordena acelerar hasta que la velocidad hasta que la velocidad sea de 60 mll/h. si la operación dura 30 minutos.

A cual fue la aceleracion?

B qué distancia recorre?

Responder:

30 millas / hora

26.25 mi

Explicación:

Dado que :

Velocidad inicial, u = 45 mi / hr

Velocidad final, v = 60 mi / hr

Tiempo, t = 30 minutos = 30/60 = 0,5 h

Aceleración, a = cambio de velocidad con el tiempo;

a = (v - u) / t

a = (60 - 45) / 0,5

a = 15 / 0,5

a = 30 millas / h²

Recorrido de distancia, S

S = ut + 0.5at²

S = 45 (0,5) + 0,5 (30) (0,5²)

S = 22,5 + 3,75

S = 26,25 millas

4 0

3 years ago