All categories

2 years ago

Please annswer will the correct letter I WILL GIVE BRAINLIEST MUST ANSWER BOTH :)

Physics

1 answer:

erica [24]2 years ago

3 0

C and A the first one is a bit weird but thats what i got and you cant even see it that good

You might be interested in

What wave is a wave in which the vibration of the medium is parallel to the direction the wave travels.?

galina1969 [7]

The answer to this question would be a transverse wave, because the vibration travels parallel to the direction that the wave is traveling.

7 0

2 years ago

A car horn creates a 595 Hz tone

aliina [53]

Answer:

529 Hz

Explanation:

595(343-20)/(343 + 20) = 529

3 0

3 years ago

Light enters an equilateral prism with an incident angle of 35Â° to the normal of the surface. Calculate the angle at which the

julia-pushkina [17]

Answer:

65.9°

Explanation:

When light goes through air to glass

angle of incidence, i = 35°

refractive index, n = 1.5

Let r be the angle of refraction

Use Snell's law

$n=\frac{Sini}{Sinr}$

$1.5=\frac{Sin35}{Sinr}$

Sin r = 0.382

r = 22.5°

Now the ray is incident on the glass surface.

A = r + r'

Where, r' be the angle of incidence at other surface

r' = 60° - 22.5° = 37.5°

Now use Snell's law at other surface

$\frac{1}{n}=\frac{Sinr'}{Sini'}$

Where, i' be the angle at which the light exit from other surface.

$\frac{1}{1.5}=\frac{Sin37.5'}{Sini'}$

Sin i' = 0.913

i' = 65.9°

4 0

2 years ago

Fg =G m1m2/r2 solver for G

Blababa [14]

G = $\frac{F_{g} r^{2} }{m_{1} m_{2} }$

Explanation:

Solving for G simply implies that we make G the subject of the formula:

Given equation:

F $_{g}$ = G $\frac{m_{1} m_{2} }{ r^{2} }$

To make G the subject of this expression follow these steps:

Multiply both sides of the equation by $r^{2}$

F $_{g}$ x $r^{2}$ = G $\frac{m_{1} m_{2} }{ r^{2} }$ x $r^{2}$

This gives:

F $_{g}$ $r^{2}$ = G $m_{1} m_{2}$

Multiply both sides by $\frac{1}{m_{1} m_{2} }$

F $_{g}$ $r^{2}$ x $\frac{1}{m_{1} m_{2} }$ = $\frac{1}{m_{1} m_{2} }$ x G $m_{1} m_{2}$

Therefore:

G = $\frac{F_{g} r^{2} }{m_{1} m_{2} }$

Learn more:

Solving formula brainly.com/question/2998489

#learnwithBrainly

6 0

2 years ago

A Rac variant, in which the residue at position 61 was replaced with an alanine (Rac61A), was synthesized. Wild-type Rac and Rac

ludmilkaskok [199]

Answer:

Ammonia, $(NH_{3})$

Explanation:

If a Rac variant, in which the residue at position 61 was replaced with an alanine (Rac-61A), was synthesized. Also, Wild-type Rac and Rac-61A were incubated separately with VopC.

In order to obtain data to support that VopC modifies Rac at residue 61, the samples should be analyzed for the presence of Ammonia ( $NH_{3}[\tex]) compound.In chemistry, the Vanadyl Phthalocyanine (VopC) comprises of a catalytic domain that activates host cells GTPase Rac irreversibly, through the deamide side chain of the residue existing at position 61.Also, we know that a deamidation reaction gives off Ammonia, [tex](NH_{3})$ and as such when ammonia is present in the sample containing Wild-type Rac but not in Rac-61A, this simply proves or provide the data to support that VopC modifies Rac at residue 61.

<em>Additionally, deamidation can be defined as the chemical conversion (hydrolysis) of an amide functional group such as glutamine, asparagine, in a polypeptide to another functional group such as glutamic acid or isoaspartic acid respectively by treating it with a strong acid (deamidate, transamidase). </em>

3 0

2 years ago