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2 years ago

11

A drawer contains 4 red socks, 5 white socks, and 6 blue socks. Without looking, you draw out a sock and then draw out a second

sock without replacement. What is the probability that the first and the second sock are both white?

1 answer:

mezya [45]2 years ago

6 0

The probability is (4/16) * (10/16) = 5/32

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<u>7. Ans</u>;

$\frac{6 {a}^{5} {b}^{7} }{ - 2 {a}^{3} {b}^{7} } = \frac{2 {a}^{3} {b}^{7}(3 {a}^{2} ) }{ - 2 {a}^{3} {b}^{7} } = - 3 {a}^{2}$

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<u>8. Ans</u>;

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<u>9. Ans</u>;

$\frac{ - 16 a {b}^{4} }{4 {b}^{3} } = \frac{4 {b}^{3}( - 4ab) }{4 {b}^{3} } = - 4ab$

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<u>10. Ans;</u>

$\frac{21 {m}^{8} {n}^{5} }{27 {m}^{5} {n}^{4} } = \frac{3 {m}^{5} {n}^{4}(7 {m}^{3} n) }{3 {m}^{5} {n}^{4}(9) } = \frac{7 {m}^{3}n }{9}$

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<u>11. Ans;</u>

$\frac{ - 15 {x}^{5} {y}^{4} }{45x {y}^{3} } = \frac{ 15x {y}^{3} ( - {x}^{4} y)}{15x {y}^{3}(3) } = - \frac{ {x}^{4}y }{3}$

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<u>12.Ans;</u>

$\frac{7 {p}^{2} {q}^{2} }{14 {p}^{2} {q}^{2} } = \frac{7 {p}^{2} {q}^{2} }{7 {p}^{2} {q}^{2} (2) } = \frac{1}{2} = 0.5$

I hope I helped you^_^

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2 years ago

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