The Slope of a Line
Suppose we know the line passes through points A(x1,y1) and B(x2,y2). The slope can be calculated with the equation:

The graph provided suggests the use of the points (3,-3) and (5,-3). The slope is:

The slope of the line is 0. It corresponds to a horizontal line
Answer: x = 3
Step-by-step explanation:
Simplifying
17x + -3 = 48
Reorder the terms:
-3 + 17x = 48
Solving
-3 + 17x = 48
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '3' to each side of the equation.
-3 + 3 + 17x = 48 + 3
Combine like terms: -3 + 3 = 0
0 + 17x = 48 + 3
17x = 48 + 3
Combine like terms: 48 + 3 = 51
17x = 51
Divide each side by '17'.
x = 3
Simplifying
x = 3
Answer:
x = -4
Step-by-step explanation:
Step 1: Define
j(x) = 3x + 1
j(x) = -11
Step 2: Substitute and solve for <em>x</em>
-11 = 3x + 1
-12 = 3x
x = -4
Answer:
X = 4√3
Step-by-step explanation:
Using tangent-secant theorem
So,
X² = (4)(4+8)
X² = (4)(12)
X² = (48)
Taking sqrt on both sides
X = 4√3
Solution :
Given data :
20.1 33.5 21.7 58.4 23.2 110.8 30.9
24.0 74.8 60.0
n = 10
Range : Arranging from lowest to highest.
20.1, 21.7, 23.2, 24.0, 30.9, 33.5, 58.4, 60.0, 74.8, 110.8
Range = low highest value - lowest value
= 110.8 - 20.1
= 90.7
Mean = 



Sample standard deviation :





S = 29.8644
Variance = 

= 891.8823