I’m the expression 10a + 4, identify the coefficient

Which statement about scatter plots is true? A. Associated variables cannot be represented on scatter plots B. A regression line

Ratling [72]

A scatter plot or also called the scatter graph, chart or diagram is a type of plot or mathematical diagram using Cartesian coordinates to display value for typically two variables for set of data. Base on that fact, the possible answer to your question is letter D. Scatter plot can be used to represent quantitative data

3 0

3 years ago

Read 2 more answers

The table below shows the results of a survey conducted among the employees of a company to find the preferred choices for inves

gladu [14]

Answer: B

Step-by-step explanation:

Took the test

6 0

2 years ago

3. Use the diagram of a REGULAR HEXAGON and follow these steps to solve for the area of a hexagon with sides equal to 4 cm. Leav

Delicious77 [7]

Answer:

There are 6 equilateral triangles

you get an isosceles triangle

the height of the equilateral triangle is 4

this is all I have so far :)

3 0

3 years ago

2818 people ferried to an island. If the ferry took 70 people in one trip, how many trips did the ferry make.

sasho [114]

Answer:

41

Step-by-step explanation:

Divide 2818 by 70 and it comes out to: 40.2571429 it is not 40 because their is still some left over so there will be 41 ferry's and one of them will not be a full ride!

5 0

2 years ago

Maths functions question!!

Marina86 [1]

Answer:

5) DE = 7 units and DF = 4 units

6) ST = 8 units

$\textsf{7)} \quad \sf OM=\dfrac{3}{2}\:units$

8) x ≤ -3 and x ≥ 3

Step-by-step explanation:

<u>Information from Parts 1-4:</u>

brainly.com/question/28193969

$f(x)=-x+3$

$g(x)=x^2-9$

A = (3, 0) and C = (-3, 0)

Points A and D are the <u>points of intersection</u> of the two functions.

To find the x-values of the points of intersection, equate the two functions and solve for x:

$\implies g(x)=f(x)$

$\implies x^2-9=-x+3$

$\implies x^2+x-12=0$

$\implies x^2+4x-3x-12=0$

$\implies x(x+4)-3(x+4)=0$

$\implies (x-3)(x+4)=0$

Apply the zero-product property:

$\implies (x-3)= \implies x=3$

$\implies (x+4)=0 \implies x=-4$

From inspection of the graph, we can see that the x-value of point D is <u>negative</u>, therefore the x-value of point D is x = -4.

To find the y-value of point D, substitute the found value of x into one of the functions:

$\implies f(-4)=-(-4)=7$

Therefore, D = (-4, 7).

The length of DE is the difference between the y-value of D and the x-axis:

⇒ DE = 7 units

The length of DF is the difference between the x-value of D and the x-axis:

⇒ DF = 4 units

To find point S, substitute the x-value of point T into function g(x):

$\implies g(4)=(4)^2-9=7$

Therefore, S = (4, 7).

The length ST is the difference between the y-values of points S and T:

$\implies ST=y_S-y_T=7-(-1)=8$

Therefore, ST = 8 units.

The given length of QR (⁴⁵/₄) is the difference between the functions at the same value of x. To find the x-value of points Q and R (and therefore the x-value of point M), subtract g(x) from f(x) and equate to QR, then solve for x:

$\implies f(x)-g(x)=QR$