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aev [14]
3 years ago
9

Find the 250th term of the sequence below 57, 66, 75, 84, 93

Mathematics
1 answer:
Paul [167]3 years ago
4 0
Hello :
93-84 =84-75 = 75-66 = 66-57 = 9 ...( common diference of arithmetic <span>sequence )
Un = U1 + (n-1)d             d= 9 and   U1 = 57    n = 250
U250 = 57 +249(9) = 2298</span>
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Could someone answer and explain these please? Thank you!
Oksana_A [137]

Answer 1:

It is given that the positive 2 digit number is 'x' with tens digit 't' and units digit 'u'.

So the two digit number x is expressed as,

x=(10 \times t)+(1 \times u)

x=10t+u

The two digit number 'y' is obtained by reversing the digits of x.

So, y=(10 \times u)+(1 \times t)

y=10u+t

Now, the value of x-y is expressed as:

x-y=(10t+u)-(10u+t)

x-y=10t+u-10u-t

x-y=9t-9u

x-y=9(t-u)

So, 9(t-u) is equivalent to (x-y).

Answer 2:

It is given that the sum of infinite geometric series with first term 'a' and common ratio r<1 = \frac{a}{1-r}

Since, the sum of the given infinite geometric series = 200

Therefore,\frac{a}{1-r}=200

Since, r=0.15 (given)

\frac{a}{1-0.15}=200

\frac{a}{0.85}=200

a=0.85 \times 200

a=170

The nth term of geometric series is given by ar^{n-1}.

So, second term of the series = ar^{2-1} = ar

Second term = 170 \times 0.15

= 25.5

So, the second term of the geometric series is 25.5






Step-by-step explanation:


8 0
3 years ago
A fair coin is flipped twelve times. What is the probability of the coin landing tails up exactly nine times?
seraphim [82]

Answer:

P\left(E\right)=\frac{55}{1024}

Step-by-step explanation:

Given that a fair coin is flipped twelve times.

It means the number of possible sequences of heads and tails would be:

2¹² = 4096

We can determine the number of ways that such a sequence could contain exactly 9 tails is the number of ways of choosing 9 out of 12, using the formula

nCr=\frac{n!}{r!\left(n-r\right)!}

Plug in n = 12 and r = 9

       =\frac{12!}{9!\left(12-9\right)!}

       =\frac{12!}{9!\cdot \:3!}

       =\frac{12\cdot \:11\cdot \:10}{3!}            ∵ \frac{12!}{9!}=12\cdot \:11\cdot \:10

       =\frac{1320}{6}                   ∵ 3!\:=\:3\times 2\times 1=6

       =220

Thus, the probability will be:

P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}

         =\frac{220}{4096}

         =\frac{55}{1024}

Thus, the probability of the coin landing tails up exactly nine times will be:

P\left(E\right)=\frac{55}{1024}

4 0
3 years ago
You must use the LCD 1/7 + 3/14 *Convert Into into like fractions and add them
Tresset [83]
The LCD of 1/17 and 3/14 is 14.

1/7 = 2/14

3/14 = 3/14

2 + 3 = 5

The denominators are the same, so it will remain the same.

= 5/14 <===

5/14 is your answer.


I hope this helps! :)
3 0
3 years ago
Read 2 more answers
Identify the x-intercept and y-intercept of the equation below.
Lady_Fox [76]
Divide by 21 to put the equation in intercept form.
  x/(21/9) + y/(-21/7) = 1
  x/(7/3) + y/(-3) = 1

The x-intercept is (7/3, 0)
The y-intercept is (0, -3)

The 3rd choice is appropriate.

8 0
3 years ago
Help plz:)))I’ll mark u Brainliest
zheka24 [161]

Answer: The answer is 10

3 0
2 years ago
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