All categories

2 years ago

A circle has a radius of sqrt 37 units and is centered at (1.3, -3.5) write the equation fo the circle

Mathematics

1 answer:

lina2011 [118]2 years ago

5 0

Answer:

(x-1.3)^2 + (y+3.5)^2 = 37

Step-by-step explanation:

The equation of a circle is given by

(x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center and r is the radius

(x-1.3)^2 + (y--3.5)^2 = (sqrt(37))^2

(x-1.3)^2 + (y+3.5)^2 = 37

You might be interested in

Please I need help!!!

Natalija [7]

Answer:

Step-by-step explanation:

-14 + x = 44

x = 44 + 14

x = 58

3 0

2 years ago

An ore ship is traveling west toward Duluth on Lake Superior at 18 miles per hour. The bearing of Split Rock Lighthouse is 285de

goblinko [34]

We are given
v = 18 m/hr west
θ1 = 285°
θ2 = 340°

After 1 hours, the distance traveled by the ship is
dv = 18 mi

The distance between the ship and the lighthouse is
d = 18 / cos 340
Solve for d

5 0

3 years ago

Look at the picture of a scaffold used to support construction workers. The height of the scaffold can be changed by adjusting t

maria [59]

Part A

Using the Pythagorean on the right triangle PQR, with PQ and QR as the legs and PR as the hypotenuse,

$14^2 +6^2 =(PR)^2\\\\(PR)=\sqrt{14^2 +6^2}\\\\PR \approx \boxed{15.23 \text{ ft}}$

Part B

$(QR)^2 +6^2 =16^2\\\\(QR)^2 =16^2 -6^2\\\\QR=\sqrt{16^2 -6^2}\\\\QR \approx \boxed{14.83 \text{ ft}}$

8 0

1 year ago

A population proportion is . A sample of size will be taken and the sample proportion will be used to estimate the population pr

padilas [110]

Complete Question:

A population proportion is 0.4. A sample of size 200 will be taken and the sample proportion p will be used to estimate the population proportion. Use z- table Round your answers to four decimal places. Do not round intermediate calculations. a. What is the probability that the sample proportion will be within ±0.03 of the population proportion? b. What is the probability that the sample proportion will be within ±0.08 of the population proportion?

Answer:

A) 0.61351

Step-by-step explanation:

Sample proportion = 0.4

Sample population = 200

A.) proprobaility that sample proportion 'p' is within ±0.03 of population proportion

Statistically:

P(0.4-0.03<p<0.4+0.03)

P[((0.4-0.03)-0.4)/√((0.4)(.6))/200 < z < ((0.4+0.03)-0.4)/√((0.4)(.6))/200

P[-0.03/0.0346410 < z < 0.03/0.0346410

P(−0.866025 < z < 0.866025)

P(z < - 0.8660) - P(z < 0.8660)

0.80675 - 0.19325

= 0.61351

B) proprobaility that sample proportion 'p' is within ±0.08 of population proportion

Statistically:

P(0.4-0.08<p<0.4+0.08)

P[((0.4-0.08)-0.4)/√((0.4)(.6))/200 < z < ((0.4+0.08)-0.4)/√((0.4)(.6))/200

P[-0.08/0.0346410 < z < 0.08/0.0346410

P(−2.3094 < z < 2.3094)

P(z < -2.3094 ) - P(z < 2.3094)

0.98954 - 0.010461

= 0.97908

6 0

3 years ago

HELP ASAP!!! Tried everything but still no correct answer. Someone please help. Thank you for your help!!!

Stella [2.4K]

Answer:

Example 0-30 in 0-5 5-10 10-15 etc... upto 25-30

a) 12 and 15 or 10 and 15

b) none

c) none

a) Confidence Level Margin of Error Error Bar

68.3%, sx 12.2857 ±2.275 (±18.52%)

so a0 could be also 12.2857 - 2.275 = 10

Answer therefore may be 10 and 15

So try do a histogram go in 10's across 1-10,10-20,20-30,30-40,40-50

And if mean is 43 then you would need to multiply everything inside box by 0.3 before you can start the y axes

questions like this start with 0 - 50

8 0

2 years ago