Answer:
Jana had 8 oranges, and Jordan had 15 oranges.
Step-by-step explanation:
First, identify what you know:
1) In total, Jana and Jordan had 23 oranges.
2) Jana had 7 less oranges than Jordan.
We can create a formula, where x equals the number of oranges Jana has.
23 = x + (x + 7)
16 = x + x (subtracted 7 from both sides)
x = 8 (divided both sides by 2)
So, now we know Jana had 8 oranges, which is 7 less than Jordan.
8 + 7 = ?
? = 15
Jana had 8 oranges, while Jordan had 15, for a total of 23 oranges.
I’m RIGHT here how can I help, there is no photo.
<u>Zeros of the function</u>
f(x) = (x + 2)² - 25
f(x) = (x + 2)(x + 2) - 25
f(x) = x(x + 2) + 2(x + 2) - 25
f(x) = x(x) + x(2) + 2(x) + 2(2) - 25
f(x) = x² + 2x + 2x + 4 - 25
f(x) = x² + 4x + 4 - 25
f(x) = x² + 4x - 21
x² + 4x - 21 = 0
x = <u>-(4) +/- √((4)² - 4(1)(-21))</u>
2(1)
x = <u>-4 +/- √(16 + 84)</u>
2
x = <u>-4 +/- √(100)
</u> 2<u>
</u>x = <u>-4 +/- 10
</u> 2<u>
</u>x = -2 <u>+</u> 5<u>
</u>x = -2 + 5 x = -2 - 5
x = 3 x = -7
f(x) = x² + 4x - 21
f(3) = (3)² + 4(3) - 21
f(3) = 9 + 12 - 21
f(3) = 21 - 21
f(3) = 0
(x, f(x)) = (3, 0)
or
f(x) = x² + 4x - 21
f(-7) = (-7)² + 4(-7) - 21
f(-7) = 49 - 28 - 21
f(-7) = 21 - 21
f(-7) = 0
(x, f(x)) = (-7, 0)
<u>Vertex</u>
<u>X - Intercept</u>
<u />-b/2a = -(4)/2(1) = -4/2 = -2
<u>Y - Intercept</u>
y = x² + 4x - 21
y = (-2)² + 4(-2) - 21
y = 4 - 8 - 21
y = -4 - 21
y = -25
(x, y) = (-2, -25)
<u />
Answer:
O weight in kilograms = 25 x 3.5 ÷ 2.2
Step-by-step explanation:
As a butcher, you sell beef in 3.5-pound packages. You anticipate needing 25 packages for the next two days.
Therefore, the total number of pounds for the 25 packages =
3.5 pound packages × 25
= 87.5 pounds
We are told that : The wholesaler from whom you purchase large pieces of meat measures the weight of the beef in kilograms.
Note that:
2.2 pounds = 1 kg
Hence:
87.5 pounds =
= 87.5÷ 2.2
= 39.772727273 kg
He needs to buy 39.772727273kg from the wholesaler
The equation can you use to determine the weight of the beef, in kilograms, that you need to purchase from the wholesaler is:
O weight in kilograms = (25 x 3.5) ÷ 2.2
A.
(0,00
(2.6,7.9)
(4.8,12.4)
(9.7,15.1)
b.
well, the points don't look like they are on the line but they actually are (plot twist)
so
since (0,0) is on th egarph
0=a(0)²+b(0)+c
0=c
so
f(x)=ax²+bx+0 or
f(x)=ax²+bx
find a and b
sub points
(2.6,7.9)
7.9=a(2.6)²+b(2.6)
7.9=6.76a+2.6b
(4.8,12.4)
12.4=a(4.8)²+b(4.8)
12.4=23.04a+4.8b
use those 2 equations
7.9=6.76a+2.6b
12.4=23.04a+4.8b
eliminate b
multiply first equation by -4.8 and 2nd by 2.6 and add them
-37.92=-32.448a-12.48b
32.24=59.904a-12.48b +
-5.68=27.456a+0b
-5.68=27.456a
divide both sides by 27.456
(-5.68/27.456)=a
find b
12.4=23.04a+4.8b
12.4=(-130.8672/27.456)+4.8b
12.4+(130.8672/27.456)=4.8b
(12.4+(130.8672/27.456))/4.8=b
da equation is

c. the roots are found with your calculator
the roots are at x=0 and x=17.287323943662
so very close to the target but not exactly on it
if the target has a radius of 0.287323943662 or more then it will hit the target