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Ostrovityanka [42]
3 years ago
9

Suppose that A = {2, 4, 6}, B = {2, 6}, C = {4, 6}, and D = {4, 6, 8}. Identify the pairs of sets in which one is a subset of th

e other (in any order)
Mathematics
2 answers:
OLEGan [10]3 years ago
7 0

Answer:

Step-by-step explanation:

Given that A = {2, 4, 6}, B = {2, 6}, C = {4, 6}, and D = {4, 6, 8}.

We know that P is a subset of Q if all elements of P are also in Q

Using this let us compare pairwise

A and B

The elements of B are also in A

So B is a subset of A

Next A and C,

All elements of C are in A.  So C is a subset of A

B and C.  We find neither is a subset of other

B and D.  Here also 2 is not in D so not a subset

C and D

C is a subset of D

SO answer is

B and C are subsets of A and C is also a subset of D

Alona [7]3 years ago
5 0

Answer:

B is a subset of A

C is a subset of A

C is a subset of D

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Hello!

First, let's write the problem.
3\left(x-2\right)+2\left(x+1\right)=-14
Apply the distributive property on the left side of the equation.
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Add like terms.
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Let's plug that in into the original equation.
5x-4=-14
Add 4 to both sides.
5x-4+4=-14+4
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Divide both sides by 5.
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Our final answer would be,
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You can feel free to let me know if you have any questions regarding this!
Thanks!

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