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Ostrovityanka [42]
3 years ago
9

Suppose that A = {2, 4, 6}, B = {2, 6}, C = {4, 6}, and D = {4, 6, 8}. Identify the pairs of sets in which one is a subset of th

e other (in any order)
Mathematics
2 answers:
OLEGan [10]3 years ago
7 0

Answer:

Step-by-step explanation:

Given that A = {2, 4, 6}, B = {2, 6}, C = {4, 6}, and D = {4, 6, 8}.

We know that P is a subset of Q if all elements of P are also in Q

Using this let us compare pairwise

A and B

The elements of B are also in A

So B is a subset of A

Next A and C,

All elements of C are in A.  So C is a subset of A

B and C.  We find neither is a subset of other

B and D.  Here also 2 is not in D so not a subset

C and D

C is a subset of D

SO answer is

B and C are subsets of A and C is also a subset of D

Alona [7]3 years ago
5 0

Answer:

B is a subset of A

C is a subset of A

C is a subset of D

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Answer:

Options A, B, C and D

Step-by-step explanation:

This question is not complete; here is the complete question.

Tori bought 24 candy bars for 69 cents each. She used partial products to find the total cost in cents. Which are NOT possible partial products for 24 × 69?

A. 24

B. 36

C. 180

D. 240

E. 1656

Cost of one candy = 69 cents  

Since, cost of 24 candies = Cost of one candy × Number of candies

                                          = 69 × 24

For partial product,

69 × 24 = (60 + 9)(20 + 4)

             = 60(20 + 4) + 9(20 + 4)

             = 60×20 + 60×4 + 9×20 + 9×4

             = 1200 + 240 + 180 + 36

             = 1656

Therefore, Options A, B, C and D are not possible partial products.

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Step-by-step explanation:


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