Answer:
Suppose that A and B are points on the number line.
If AB=11 and A lies at 6, where could B be located?
If there is more than one location, separate them with commas
Step-by-step explanation:
Suppose that A and B are points on the number line.
If AB=11 and A lies at 6, where could B be located?
If there is more than one location, separate them with commas
Answer:
what is the question
Step-by-step explanation:
Answer:
(a) 
(b) 
(c) 
Step-by-step explanation:
We have given velocity as function of t 
Acceleration is equation rate if change of velocity with respect to time
So 
(a) Acceleration at t = 5 sec

(b) Acceleration at t = 10 sec

(c) Acceleration at t = 20 sec

Answer:
x=2, y=1
Step-by-step explanation:
2x + y = 5
5x − 2y = 8.
Multiply the first equation by 2
2( 2x + y) = 5*2
4x +2y = 10
Add this to the 2nd equation to eliminate y
4x+2y = 10
5x -2y = 8
--------------------
9x = 18
Divide by 9
9x/9 = 18/9
x = 2
Now find y
2x+y = 5
2(2)+y = 5
4+y = 5
Subtract 4 from each side
y = 5-4
y =1
Answer:
he just might be
Step-by-step explanation: