the top part solve for x by simplifying both sides of the equation then isolating the variable.
x= -175
second part solve for x by simplifying both sides of the equation then isolating the variable ;
x = -175
third part:
x = -175
fourth part;solve for x by simplifying both sides of the equation then isolating the variable
x = -175
fifth part;
x= -175
sixth part;
nothing further can be done with this topic
so its
x= -175 :p
1 second = 2 megabytes
![1\frac{1}{2}\ seconds=3\ megabytes](https://tex.z-dn.net/?f=1%5Cfrac%7B1%7D%7B2%7D%5C%20seconds%3D3%5C%20megabytes)
2 seconds = 4 megabytes
Step-by-step explanation:
Given,
Time taken to download 5 megabytes =
seconds
![\frac{5}{2}\ seconds = 5\ megabytes](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D%5C%20seconds%20%3D%205%5C%20megabytes)
Multiplying both sides by
to find unit rate
![\frac{2}{5}*\frac{5}{2}\ second = \frac{2}{5}*5\\1\ second = 2\ megabytes](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%2A%5Cfrac%7B5%7D%7B2%7D%5C%20second%20%3D%20%5Cfrac%7B2%7D%7B5%7D%2A5%5C%5C1%5C%20second%20%3D%202%5C%20megabytes)
1 second = 2 megabytes
![1\frac{1}{2}\seconds = \frac{3}{2}\ seconds](https://tex.z-dn.net/?f=1%5Cfrac%7B1%7D%7B2%7D%5Cseconds%20%3D%20%5Cfrac%7B3%7D%7B2%7D%5C%20seconds)
![\frac{3}{2}\ seconds = \frac{3}{2}*2](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%5C%20seconds%20%3D%20%5Cfrac%7B3%7D%7B2%7D%2A2)
![\frac{3}{2}\ seconds = 3\ megabytes](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%5C%20seconds%20%3D%203%5C%20megabytes)
![1\frac{1}{2}\ seconds=3\ megabytes](https://tex.z-dn.net/?f=1%5Cfrac%7B1%7D%7B2%7D%5C%20seconds%3D3%5C%20megabytes)
2 seconds = 2*2 megabytes
2 seconds = 4 megabytes
Keywords: fraction, multiplication
Learn more about fractions at:
#LearnwithBrainly
Answer:
<u>$328.52</u>
Step-by-step explanation:
let p = x, t = 6 years and r = 0.07. now the formula is x*e^0.42 = 500. e^0.42 is approx. 1.522. divide 500 by that to get about <u>$328.52</u>
Answer: the first graph
Reasoning: When a graph is going left to right it is a decay while when it’s going right to left it is an increase... think of linear equations where if it is going from left to right the slope is negative, it’s the same for the exponential decay and increase.