3 years ago

Evaluate the expression 9(a + 2b) + c for a = −3, b = −2, and c = 1.

Mathematics

2 answers:

olganol [36]3 years ago

5 0

Answer:

−62

Step-by-step explanation:

9(-3+2(-2)+1 = -62

Igoryamba3 years ago

3 0

Answer

-44

Step-by-step explanation:

9(a+2b)+c

9(-3+2*-2)+1

9(-3-2)+1

9(-5)+1

-45+1

-44

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hichkok12 [17]

According to the given plot, $f'(1)=2$ . Then the linear approximation to $f(x)$ at $x=1$ is

$L(x)=f(1)+f'(1)(x-1)=6+2(x-1)=2x+4$

Then

$f(0.95)\approx L(0.95)=5.9$

$f(1.05)\approx L(1.05)=6.1$

On the interval [0, 1], the plot of $f'(x)$ is positive, so $f(x)$ is an increasing function here. But we can see that $f'(x)$ is approaching 0. This means tangent lines to $f(x)$ have a positive slope, but the slopes are approaching 0 and are thus becoming less steep. This in turn means the tangent lines lie above the curve, so the approximations are greater than the actual values of $f(0.95)$ and $f(1.05)$ .