M=-1
4m+2(m+1)=9m +5
4m+2m+2=9m+5
6m+2=9m+5
6m+2-6m= 9m+5-6m
2-5=3m+5-5
-3/3=3m/3
m=-1
Let the faculties be X and the number of students be Y.
X/Y = 17/3
3X= 17Y
X=17Y/3
Let that be equation 1
We also know that X+Y = 740. Let it be equation 2
Substitute equation 1 in equation 2
(17Y/3)+Y= 740
20Y/3 = 740
Y=111
Since the total is 740, then X equal 740-111 =629.
The number of faculties is 111 and the number of students is 629.
Answer:
56 feet
Step-by-step explanation:
If 1 inch = 2 feet, we can first find the actual dimensions of his room by multiplying the number of inches by 2.
6(2)
= 12
8(2)
= 16
So, the actual dimensions of his room are 12 feet by 16 feet.
To find the perimeter, use the perimeter formula, P = 2l + 2w.
Plug in the length and width:
P = 2l + 2w
P = 2(12) + 2(16)
P = 24 + 32
P = 56
So, the perimeter of his actual room is 56 feet.
29kn are equal to cn 2900000
Hope it was right.
K = 10
I think. I’m not positive sure though. Hope this helped!
