Use a protractor to do the problem, but try finding th answer yourself
Answer:
0.2364
Step-by-step explanation:
We will take
Lyme = L
HGE = H
P(L) = 16% = 0.16
P(H) = 10% = 0.10
P(L ∩ H) = 0.10 x p(L U H)
Using the addition theorem
P(L U H) = p(L) + P(H) - P(L ∩ H)
P(L U H) = 0.16 + 0.10 - 0.10 * p(L u H)
P(L U H) = 0.26 - 0.10p(L u H)
We collect like terms
P(L U H) + 0.10P(L U H) = 0.26
This can be rewritten as:
P(L U H)[1 +0.1] = 0.26
Then we have,
1.1p(L U H) = 0.26
We divide through by 1.1
P(L U H) = 0.26/1.1
= 0.2364
Therefore
P(L ∩ H) = 0.10 x 0.2364
The probability of tick also carrying lyme disease
P(L|H) = p(L ∩ H)/P(H)
= 0.1x0.2364/0.1
= 0.2364
2 | 10500
2 ! 5250
3 | 2625
5 | 875
5 | 175
5 | 35
7
The prime factors are 2*2*3*5*5*5*7 or 2^2*3*5^3*7
Answer:
72.175
Step-by-step explanation:
The first step is subtract 94.68 by 49.67 which would be 45.01
The next step would be to use 45.01 and divide by two
The last step would be subtract 94.68 by 22.505 and you would get 72.175
Therefore your answer would be 72.175
