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Brrunno [24]
1 year ago
9

Answer plsssssssssssssss

Mathematics
2 answers:
krek1111 [17]1 year ago
8 0

Answer:

1005.3 ft^{3}

Step-by-step explanation:

V=π r^2 h = π · 42· 20 ≈ 1005.30965 ---> 1005.3

Papessa [141]1 year ago
8 0

Answer:

the answer to this question should be 1004.8 because first you need to use this formula to find the volume of a cylinder which is V=TTr^2h so remember the radius is half of the diameter.

So the half of 8 is 4 so 4 is the radius but remember that 4 is to the power of 2 in the exponent so the answer should be 16 because you multiplied 4 times 4 equals 16.

Then we need to multiplied 16 times 3.14 and 20 and when we do that we get an answer of 1,004.8 so 1004.8 feet^3 is the correct answer.

Step-by-step explanation: :DDDDD give brainliest to the first people that answer first than me if you want and have a great day.

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Monica [59]

To find the volume we use an equation:

volume = length x width x height

Since this shape is a cube, you only need to know one side to find the volume since all of the sides are equal.

So all you need to find the volume is to multiply 4(1/2) which I am going to simplify to 4.5, is plug it into the equation.

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5 0
3 years ago
In a set of 25 aluminum castings, four castings are defective (D), and the remaining twenty-one are good (G). A quality control
lianna [129]

Answer:

The sample space for selecting the group to test contains <u>2,300</u> elementary events.

Step-by-step explanation:

There are a total of <em>N</em> = 25 aluminum castings.

Of these 25 aluminum castings, <em>n</em>₁ = 4 castings are defective (D) and <em>n</em>₂ = 21 are good (G).

It is provided that a quality control inspector randomly selects three of the twenty-five castings without replacement to test.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

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Compute the number of samples that are possible as follows:

{25\choose 3}=\frac{25!}{3!\times (25-3)!}

      =\frac{25\times 24\times 23\times 22!}{3!\times 22!}\\\\=\frac{25\times 24\times 23}{3\times 2\times 1}\\\\=2300

The sample space for selecting the group to test contains <u>2,300</u> elementary events.

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