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qwelly [4]
3 years ago
14

Does changing the compound inequality x > −3 and x < 3 from “and” to “or” change the solution set? explain.

Mathematics
2 answers:
topjm [15]3 years ago
6 0
Sure yes.

1) x > - 3 or x < 3 means that the solution set is all the numbers greater than - 3 and all the numbers smaller than 3. That is, this union of intervals: (-3,∞) U (-∞,3),  which is all the real numbers.

2) x > -3 and x <3 means that the solution set is the numbers that are at the same time greater than -3 and smaller than 3. That is the intersection of the intervals: (-3,∞) ∩ (-∞,3), which is the interval (-3, 3).
8_murik_8 [283]3 years ago
6 0
Yes. In interval notation: 

<span>x > -3 and x < 3 = (-3, 3) </span>

<span>x > -3 or x < 3 = (-inf, inf) </span>

<span>x > -3 xor x < 3 = (-inf, -3] U [3, inf) where xor is the "exclusive or", either-or but not both.</span>
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Given m || n, find the value of x and y.<br> m(7x+13)<br> n(3y-17) (9x-19)
Varvara68 [4.7K]

Answer:

9x - 19 = 7x + 13 \\ 2x = 32 \\ x = 16 \\ 3y - 17 + 9x - 19 = 180 \\ 9x + 3y = 180 + 17 + 19 \\ 9x + 3y = 216 \\ 3y = 216 - 144 = 72 \\ y =  \frac{72}{3}  = 24

4 0
3 years ago
Sin\theta +cos\theta =1
Mamont248 [21]

Answer:

θ = 2 π n_1 + π/2 for n_1 element Z  or θ = 2 π n_2 for n_2 element Z

Step-by-step explanation:

Solve for θ:

cos(θ) + sin(θ) = 1

cos(θ) + sin(θ) = sqrt(2) (cos(θ)/sqrt(2) + sin(θ)/sqrt(2)) = sqrt(2) (sin(π/4) cos(θ) + cos(π/4) sin(θ)) = sqrt(2) sin(θ + π/4):

sqrt(2) sin(θ + π/4) = 1

Divide both sides by sqrt(2):

sin(θ + π/4) = 1/sqrt(2)

Take the inverse sine of both sides:

θ + π/4 = 2 π n_1 + (3 π)/4 for n_1 element Z

or θ + π/4 = 2 π n_2 + π/4 for n_2 element Z

Subtract π/4 from both sides:

θ = 2 π n_1 + π/2 for n_1 element Z

or θ + π/4 = 2 π n_2 + π/4 for n_2 element Z

Subtract π/4 from both sides:

Answer: θ = 2 π n_1 + π/2 for n_1 element Z

or θ = 2 π n_2 for n_2 element Z

4 0
3 years ago
Can someone help me find the answer?
den301095 [7]

Answer:

that sucks


Step-by-step explanation:


5 0
3 years ago
If f, g, h
ale4655 [162]

Answer:

F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x

F(3) = 3(3)^2 + 1 = 27 + 1 = 28

G(4) = 2(4) - 3 = 8 - 3 = 5

2H(5) = 2(5) = 10

F(3) + G(4) - 2H(5) = 28 + 5 - 10

F(3) + G(4) - 2H(5) = 23

Step-by-step explanation:

I believe I'm not sure tho

6 0
3 years ago
Y=3x+8 Y=-2x-2<br>can anyone help me with this ??
vivado [14]
Is it 2 different questions or just one?
6 0
3 years ago
Read 2 more answers
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