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3 years ago

I really need help with this algebra problem: 5a=89

Mathematics

1 answer:

stiks02 [169]3 years ago

4 0

Divide 5 by 89 and you get a=17.8

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Simplify (4y - 3x - 2) - (7y + 4x + 3)

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Answer:

-7x - 3y -5

Step-by-step explanation:

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2 years ago

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What is a solution to (x + 6)(x + 2) = 60?

Reika [66]

Solution of the equation $(x+6)(x+2)=60$ is x=4 and x=-12

Step-by-step explanation:

We need to solve the equation: $(x+6)(x+2)=60$

Solving:

$(x+6)(x+2)=60$

Multiplying terms on the left hand side

$x(x+2)+6(x+2)=60$

$x^2+2x+6x+12=60$

$x^2+8x+12=60$

$x^2+8x+12-60=0$

$x^2+8x-48=0$

Now factorizing:

$x^2+12x-4x-48=0$

$x(x+12)-4(x+12)=0$

$(x-4)(x+12)=0$

$(x-4)=0\,\,and\,\,(x+12)=0$

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So, solution of the equation $(x+6)(x+2)=60$ is x=4 and x=-12

Keywords: Solving Equations

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3 years ago

what is the volume of a cylinder with height of 9 inches and the the radius is 1 inch. round to the nearest cubic inch

poizon [28]

Answer:

Step-by-step explanation:

Volume of cylinder can be calculated by using the formula V= pir^2h

Where r is radius of cylinder and h is the height.

A cylinder with radius 1 inch and height of 9 inch is given.

r=1,h=1,π=3.14.

Substituting the given values :

V=πr2h=π·12·9≈28.27433

Volume of cylinder rounded to nearest tenth is 28.27 cubic inches .

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3 years ago

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evablogger [386]

Answer:

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Step-by-step explanation:

Given the quadratic function

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we have to find the leading coefficient of given quadratic equation.

$\text{The general form of quadratic equation is }ax^2+bx+c=0$

The coefficient of $x^2$ i.e a is known as the leading coefficient.

Comparing given equation with the standard equation, we get

a=-2

$\text{Hence, -2 is the leading coefficient of the quadratic equation }f(x)=-2x^2+5x-4$

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At a store, notebooks are on sale for 78% off the regular price. The cost of a notebook is represented by n. Which of the

zlopas [31]

Answer:

Step-by-step explanation:

If the cost is represented by n, why would you subtract the cost of the notebook by 0.78 while multiping it witht the cost?

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