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White raven [17]
3 years ago
5

Annie walks 15 feet away from her house and places a mirror on the ground. She backs 4 feet away from the mirror so that she can

see the tip of the roof. Annie's eyes are 5 feet above the ground. Annie and the house are both perpendicular to the ground. The angles between the top of the house, the mirror, and the ground and between Annie's eyes, the mirror, and the ground are congruent as shown in the image below: Image depicts a mirror on the ground between a person and a house. The mirror is 4 feet away from the person and 15 feet away from the house. What is the height of the house? Show your work and explain your reasoning in complete sentences.

Mathematics
2 answers:
Firdavs [7]3 years ago
7 0

Answer:

18.75 ft

Step-by-step explanation:

The given scenario can be drawn as shown in the following attachment.

Given that,

m\angle DCE=\angle ACB and m\angle DEC=\angle ABC=90^{\circ}

Therefore, \Delta ABC\sim \Delta DEC

\Rightarrow \dfrac{AB}{DE}=\dfrac{BC}{EC}

\Rightarrow \dfrac{AB}{5}=\dfrac{15}{4}

\Rightarrow AB=\dfrac{15\times 5}{4}=18.75 ft

AB is the height of the house.

Shkiper50 [21]3 years ago
4 0

Answer:

The roof is 18.75 ft tall.

Step-by-step explanation:

You set up a proportion by taking the height of the house (x) divided by the height of her eyes (5) is equal to the distance between the mirror and the house (15) divided by the distance between her and the mirror (4).

Then you multiply each side by 5 to get x by itself which gives you 75/4 and you simplify that to get 18.75 ft.

heres what all of that looks like:

x/5 = 15/4

x = 5(15/4)

x = 75/4

x = 18.75

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Answer:

Step-by-step explanation:

The admission to the fair is $5 and the cost per ride is 50 cents.

Let the number of rides that he can go on be x

If one ride costs 50 cents, x rides will cost 50×x = 50x cents. Converting 50 cents to dollar, it becomes 50/100 = $0.5.

So x rides will cost $0.5x

If his parents gave him $20, he will pay $5 to be admitted into the fair. He would be left with 20- 5 = $15

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The manager at a sports radio station will be covering several football games over the weekend. She knows that most of her liste
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Complete Question:

The manager at a sports radio station will be covering several football games over the weekend. She knows that most of her listeners are at least 22 years old and wants to know what age group she should gear her advertisements to for the games. She takes a random sample of 46 listeners from age 22-39 and 57 listeners who are 40 and older and asks them if they are likely to tune in to football games. The "yes" responses are recorded in the file attached below.

1. At the 0.05 level of significance, is there a significant difference in the proportion of listeners based on age?

2. Is there evidence to suggest that there is a significant difference in the proportion of listeners based on age?

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1) There is no significant difference in the proportion of listeners based on age

2) No, there is no evidence

Step-by-step explanation:

Sample size of group 1, n_1 = 46

Sample size of group 2, n_2 = 57

Number of Yes in group 1,  X_1 = 32

Number of Yes in group 2, X_2 = 47

Proportion of Yes in group 1:

\hat{p_1} = \frac{X_1}{n_1} \\\hat{p_1} = \frac{32}{46}\\\hat{p_1} = 0.6957

Proportion of Yes in group 2:

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Null Hypothesis, H_0: p_1 = p_2

Alternate Hypothesis,H_a: p_1 \neq p_2

\hat{p} = \frac{X_1 + X_2}{n_1 + n_2}  \\\\\hat{p} = \frac{ 32+47}{46+57} \\\\\hat{p}= 0.767

Significance level,

Calculate the test statistic

z = (\hat{p_1} - \hat{p_2})/\sqrt{(\hat{p} * (1-\hat{p}) * (\frac{1}{N_1}  + \frac{1}{N_2})}\\\\z = (0.6957-0.8246)/ \sqrt{(0.767*(1-0.767)*(1/46 + 1/57))}\\\\z = -1.54

Get the P-value from the probability distribution table:

At z = -1.54, P-value = 0.1236

Since (P-value = 0.1236) > (α = 0.05), we will accept the null hypothesis. This means that there is no evidence to suggest that there is difference in the proportion of listeners based on age.

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