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mr Goodwill [35]
3 years ago
12

A warehouse employs 21 workers on first​ shift, 15 workers on second​ shift, and 13 workers on third shift. Eight workers are ch

osen at random to be interviewed about the work environment. Find the probability of choosing exactly two second shift workers and two third shift workers.
Mathematics
1 answer:
Crank3 years ago
3 0

Answer: Our required probability is 0.11.

Step-by-step explanation:

Since we have given that

Number of workers in first shift = 21

Number of workers in second shift = 15

Number of workers in third shift = 13

We need to find the probability of choosing exactly two second shift workers and two third shift workers.

So, it becomes,

\dfrac{^{15}C_2\times ^{13}C_2\times ^{21}C_4}{^{49}C_8}\\\\=0.11

Hence, our required probability is 0.11.

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The minimum amount of points required to make a plane is 3 points.
4 0
3 years ago
Read 2 more answers
The volume (in cubic inches) of a shipping box is modeled by V =2x³ -19x² +39x, where x is the length (in inches). Determine the
yawa3891 [41]

Answer:

The values of x for which the model is 0 ≤ x ≤ 3

Step-by-step explanation:

The given function for the volume of the shipping box is given as follows;

V = 2·x³ - 19·x² + 39·x

The function will make sense when V ≥ 0, which is given as follows

When V = 0, x = 0

Which gives;

0 = 2·x³ - 19·x² + 39·x

0 = 2·x² - 19·x + 39

0 = x² - 9.5·x + 19.5

From an hint obtained by plotting the function, we have;

0 = (x - 3)·(x - 6.5)

We check for the local maximum as follows;

dV/dx = d(2·x³ - 19·x² + 39·x)/dx = 0

6·x² - 38·x + 39 = 0

x² - 19/3·x + 6.5 = 0

x = (19/3 ±√((19/3)² - 4 × 1 × 6.5))/2

∴ x = 1.288, or 5.045

At x = 1.288, we have;

V = 2·1.288³ - 19·1.288² + 39·1.288 ≈ 22.99

V ≈ 22.99 in.³

When x = 5.045, we have;

V = 2·5.045³ - 19·5.045² + 39·5.045≈ -30.023

Therefore;

V > 0 for 0 < x < 3 and V < 0 for 3 < x < 6.5

The values of x for which the model makes sense and V ≥ 0 is 0 ≤ x ≤ 3.

8 0
3 years ago
The probability distribution for the rate of return on an investment is
babymother [125]

Answer:

a)0.7

b) 10.03

c)  0.0801

Step-by-step explanation:

Rate of return   Probability

9.5                           0.1

9.8                           0.2

10                             0.3

10.2                          0.3

10.6                          0.1

a.

P(Rate of return is at least 10%)=P(R=10)+P(R=10.2)+P(R=10.6)

P(Rate of return is at least 10%)=0.3+0.3+0.1

P(Rate of return is at least 10%)=0.7

b)

Expected rate of return=E(x)=sum(x*p(x))

Rate of return(x)   Probability(p(x))    x*p(x)

9.5                           0.1                       0.95

9.8                           0.2                      1.96

10                             0.3                        3

10.2                          0.3                        3.06

10.6                          0.1                       1.06

Expected rate of return=E(x)=sum(x*p(x))

Expected rate of return=0.95+1.96+3+3.06+1.06=10.03

c)

variance of the rate of return=V(x)=sum(x^2p(x))-[sum(x*p(x))]^2

Rate of return(x)   Probability(p(x))    x*p(x)    x²*p(x)

9.5                           0.1                       0.95       9.025

9.8                           0.2                      1.96         19.208

10                             0.3                       3             30

10.2                          0.3                       3.06        31.212

10.6                          0.1                       1.06         11.236

sum[x²*p(x)]=9.025+19.208+30+31.212+11.236=100.681

variance of the rate of return=V(x)=sum(x²*p(x))-[sum(x*p(x))]²

variance of the rate of return=V(x)=100.681-(10.03)²

variance of the rate of return=V(x)=100.681-100.6009

variance of the rate of return=V(x)=0.0801

6 0
3 years ago
Find the arc-length parametrization of the curve that is the intersection of the elliptic cylinder x 2 + y 2/2 = 1 and the plane
storchak [24]

Answer:

f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)

0 ≤ Ф ≤ 4π.

Step-by-step explanation:

since x²+y²/2 = 1, then x²+s² = 1, with s = (y/√2)². Hence, (x,s) = (cos(Ф),sin(Ф)) and (x,y,z) = (cos(Ф),√2 sin(Ф), cos(Ф)-2). This expression evaluated in zero gives as result (1,0,-1). The derivate of this function is (-sin(Ф),√2 cos(Ф), -sen(Ф))

the norm of the derivate is √(sin²(Ф) + 2cos²(Ф)+sin²(Ф)) = √2. In order to make the norm equal to 1, i will divide Ф by √2, so that a √2 is dividing each term after derivating.

We take

f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)

Note that

  • f(0) = (1,0,-1)
  • f'(\theta) = (\frac{sin(\frac{\theta}{\sqrt2})}{\sqrt2}, cos(\frac{\theta}{\sqrt2})}, \frac{sin(\frac{\theta}{\sqrt2})}{\sqrt2})

Whose square norm is 1/2cos²(Ф/2)+sen²(Ф/2)+1/2cos²(Ф/2) = 1. This is te parametrization that we wanted.

The values from Ф range between 0 an 4π, because the argument of the sin and cos is Ф/2, not Ф, Ф/2 should range between 0 and 2π.

6 0
3 years ago
5n + 3 &gt; 4 - (6 – 5n)
jek_recluse [69]
3>-2 i believe
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4 0
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