Answer:
The probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is 0.65173.
Step-by-step explanation:
We are given that a company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 259.2 cm and a standard deviation of 2.1 cm. For shipment, 17 steel rods are bundled together.
Let = <u><em>the average length of rods in a randomly selected bundle of steel rods</em></u>
The z-score probability distribution for the sample mean is given by;
Z = ~ N(0,1)
where, = population mean length of rods = 259.2 cm
= standard deviaton = 2.1 cm
n = sample of steel rods = 17
Now, the probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is given by = P( > 259 cm)
P( > 259 cm) = P( > ) = P(Z > -0.39) = P(Z < 0.39)
= <u>0.65173</u>
The above probability is calculated by looking at the value of x = 0.39 in the z table which has an area of 0.65173.
Answer:
c or d i think
Step-by-step explanation:
Answer:
Step-by-step explanation:
1) A = x
Flower garden is in rectangular shape. In rectangle, opposite sides are equal.
2) The entire garden is in rectangular shape. In rectangle, opposite sides are equal.
B + x+ 4 = 10x + 6
Take x and 4 to other side to find the value of B. When taking to other side of equal to sign, the sign of x and 4 will change
B = 10x + 6 - x - 4
B = 10x - x + 6 - 4 {Combine like terms}
B = 9x + 2
3) C + x -2 = 5x -3
C = 5x - 3 - x +2
C = 5x -x - 3 + 2
C = 4x - 1
4) Area of Vegetable garden = length * width
= (5x - 3) * (9x + 2)
Use FOIL method
= 5x *9x + 5x*2 + (-3)*9x + (-3)*2
= 45x² + 10x - 27x - 6
= 45x² - 17x - 6
5).85 6.)100 7.)40hope this helps this id what im positive of