Answer:
n=6.56×10¹⁵Hz
Explanation:
Given Data
Mass=9.1×10⁻³¹ kg
Radius distance=5.3×10⁻¹¹m
Electric Force=8.2×10⁻⁸N
To find
Revolutions per second
Solution
Let F be the force of attraction
let n be the number of revolutions per sec made by the electron around the nucleus then the centripetal force is given by
F=mω²r......................where ω=2π n
F=m4π²n²r...............eq(i)
as the values given where
Mass=9.1×10⁻³¹ kg
Radius distance=5.3×10⁻¹¹m
Electric Force=8.2×10⁻⁸N
we have to find n from eq(i)
n²=F/(m4π²r)
Electrical things in parallel are typical of circuit elements in homes.
Electrical things in series are not typical of circuit elements in homes.
Every electrical thing in a house is in parallel. Sometimes they're also in parallel with the electrical devices in other houses nearby.
Refer to the diagram shown below.
Neglect wind resistance.
g = 9.8 m/s².
Quantities are measured as positive upward.
When the ball is launched, it has a vertical velocity of - 3.5 m/s and a horizontal velocity of 25 m/s.
The time, t, for the ball to reach the ground is
(-3.5 m/s)*( t s) - 0.5*(9.8 m/s²)*( t s)² = - (270 m)
-3.5t - 4.9t² = - 270
4.9t² + 3.5t - 270 = 0
t² + 0.71433t - 55.102 = 0
Solve with the quadratic formula.
t = 0.5[-0.71433 +/- √220.918] = 7.0745 s or -7.788 s.
Reject negative time.
The horizontal distance traveled is
d = (25 m/s)*(7.0745 s) = 176.8625 m
Answer:
The horizontal distance from the girl to the ball will be 176.9 m (nearest tenth)