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egoroff_w [7]
3 years ago
13

What happens if two small positively charged particles of equal force are placed close to each other?

Physics
2 answers:
iris [78.8K]3 years ago
6 0

Answer:

The particles will experience a repulsive force that will drive them apart along the line joining their centers.

Hope this helps, have a great day and stay safe! :) :D :3

tankabanditka [31]3 years ago
4 0

Answer:The particles will experience an attractive force causing them to meet

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Discuss velocity by providing at least one example and explain why velocity is either a scalar or vector quantity.
grandymaker [24]
Velocity is speed plus direction, so an example of velocity would be a vehicle traveling at 75mph north. Velocity is a vector quantity because it describes both magnitude and direction.
5 0
3 years ago
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What is meant by the statement that you don’t “own” the atoms that make up your body?
Zinaida [17]

Answer:

there are as many atoms in a normal breath of air as there are breathfuls of air in the atmosphere of the world

Explanation:

5 0
3 years ago
If you break a magnet in two you get
notka56 [123]
Two separate magnets.
7 0
3 years ago
An incompressible fluid flows steadily through a pipe that has a change in diameter. The fluid speed at a location where the pip
OverLord2011 [107]

Answer:

The value is v_2 =  5.53 \  m /s

Explanation:

From the question we are told

  The pipe diameter at location 1 is  d  = 8.8 \  cm =  \frac{8.8 }{10} = 0.88 \ m

   The velocity at location 1 is  v_1 =  2.4 \  m /s

   The diameter at location 2 is  d_2 =  5.80 \  cm  =  0.58 \  m

Generally the area at location 1 is  

       A_1 =  \pi *  \frac{d^2}{ 2}

=>     A_1 =  \pi *  \frac{0.88^2}{ 2}

=>     A_1 = 3.142 *  \frac{0.88^2}{ 2}

=>     A_1 = 1.2166 \  m^2

Generally the area at location 1 is  

       A_2 =  \pi *  \frac{d_1^2}{ 2}

=>     A_2 =  \pi *  \frac{0.58^2}{ 2}

=>     A_2 = 0.528  \  m^2

Generally from continuity equation we have that

     A_1 * v_1 =  A_2 * v_2

=>   1.2166 *   2.4   =  0.528   * v_2

=>   1.2166 *   2.4   =  0.528   * v_2

=>    v_2 =  5.53 \  m /s

3 0
3 years ago
Part K Find the y-component of the stone's velocity when it is 8.00 m below your hand
Romashka-Z-Leto [24]

The y-component of the stone's velocity when it is 8 m below the hand is 14.86 m / s

v² = u² + 2 a s

s = Displacement

u = Initial velocity

a = Acceleration

u = 8 m / s

s = 8 m

v² = 8² + 2 * 9.8 * 8

v² = 64 + 156.8

v = √ 220.8

v = 14.86 m / s

The equation used to solve the problem is an equation of motion. These equations are designed to locate an object in motion using components such as velocity, displacement, acceleration and time.

Therefore, the y-component of the stone's velocity is 14.86 m / s

To know more about Equations of motion

brainly.com/question/5955789

#SPJ1

4 0
1 year ago
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