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frozen [14]
2 years ago
13

State the range and the domain of this graph, is if a relation function why or why not?

Mathematics
2 answers:
Lina20 [59]2 years ago
8 0

Answer:

[-4,2]

No it is not a function.

Step-by-step explanation:

The domain is the set of X coordinates. (basically how far it goes on the x axis. This does not pass the vertical line test so it is not a function. If you draw vertical lines and the graph intersects with that line more than once it is not a function.

[,] instead of (,) because the circles are closed.

Anastaziya [24]2 years ago
5 0
(-4,2) is the answer have a great day!!!
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What is the formula for the expected number of successes in a binomial experiment with n trials and probability of success​ p? C
charle [14.2K]

Answer:

(D)E[ X ] =np.

Step-by-step explanation:

Given a binomial experiment with n trials and probability of success​ p,

f(x)=\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}, 0\leq  x\leq n

E(X)=\sum_{x=0}^{n}xf(x)= \sum_{x=0}^{n}x\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}

Since each term of the summation is multiplied by x, the value of the term corresponding to x = 0 will be 0. Therefore the expected value becomes:

E(X)=\sum_{x=1}^{n}x\left(\begin{array}{c}n\\x\end{array}\right)p^x(1-p)^{n-x}

Now,

x\left(\begin{array}{c}n\\x\end{array}\right)= \frac{xn!}{x!(n-x)!}=\frac{n!}{(x-)!(n-x)!}=\frac{n(n-1)!}{(x-1)!((n-1)-(x-1))!}=n\left(\begin{array}{c}n-1\\x-1\end{array}\right)

Substituting,

E(X)=\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^x(1-p)^{n-x}

Factoring out the n and one p from the above expression:

E(X)=np\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^{x-1}(1-p)^{(n-1)-(x-1)}

Representing k=x-1 in the above gives us:

E(X)=np\sum_{k=0}^{n}n\left(\begin{array}{c}n-1\\k\end{array}\right)p^{k}(1-p)^{(n-1)-k}

This can then be written by the Binomial Formula as:

E[ X ] = (np) (p +(1 - p))^{n -1 }= np.

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3 years ago
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6 0
2 years ago
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prisoha [69]

Answer:

about a half teaspoon

Step-by-step explanation:

4 0
2 years ago
The distance between the points (-1, -6) and (-19, -6) is units
Vladimir [108]

Answer:

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Step-by-step explanation:

\sqrt{  {( - 9 -  - 1)}^{2} +  {( - 6 -  - 6)}^{2} }

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3 0
2 years ago
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Answer:

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Sum = (497/2)[-26 - 4(497-1)]

= 497/2 * -2010

= -499,485.

3 0
3 years ago
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