State the range and the domain of this graph, is if a relation function why or why not?

Mathematics

2 answers:

Lina20 [59]2 years ago

8 0

Answer:

[-4,2]

No it is not a function.

Step-by-step explanation:

The domain is the set of X coordinates. (basically how far it goes on the x axis. This does not pass the vertical line test so it is not a function. If you draw vertical lines and the graph intersects with that line more than once it is not a function.

[,] instead of (,) because the circles are closed.

Anastaziya [24]2 years ago

5 0

(-4,2) is the answer have a great day!!!

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What is the formula for the expected number of successes in a binomial experiment with n trials and probability of success p? C

charle [14.2K]

Answer:

$(D)E[ X ] =np.$

Step-by-step explanation:

Given a binomial experiment with n trials and probability of success p,

$f(x)=\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}, 0\leq x\leq n$

$E(X)=\sum_{x=0}^{n}xf(x)= \sum_{x=0}^{n}x\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}$

Since each term of the summation is multiplied by x, the value of the term corresponding to x = 0 will be 0. Therefore the expected value becomes:

$E(X)=\sum_{x=1}^{n}x\left(\begin{array}{c}n\\x\end{array}\right)p^x(1-p)^{n-x}$

Now,

$x\left(\begin{array}{c}n\\x\end{array}\right)= \frac{xn!}{x!(n-x)!}=\frac{n!}{(x-)!(n-x)!}=\frac{n(n-1)!}{(x-1)!((n-1)-(x-1))!}=n\left(\begin{array}{c}n-1\\x-1\end{array}\right)$