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Liono4ka [1.6K]
3 years ago
13

Explain how to use the distributive property to compute 104*57 help plz

Mathematics
1 answer:
GalinKa [24]3 years ago
5 0

You can break down 104 into 100 and 4 and break down 57 into 50 and 7:

100*50

+

100*7

+

4*50

+

7*4


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AC = 16, AB = x + 1, and BC = x + 7. What is the measure of the length of AB? HELP
saveliy_v [14]

Answer:

5

Step-by-step explanation:

AC=AB+BC

so 16=x+1+x+7

which simplifies to 16=2x+8

subtract eight from both sides to get 8=2x

then divide by 2 to get that x=4

AB=x+1, which substitutes into 4+1=5

6 0
3 years ago
F(x)=bx^2+32 For the function f defined above, b is a constant and f(2)=40. What is the value of f(-2)?
zhuklara [117]

Answer:

f(-2) = 0

Step-by-step explanation:

Given that:

f(x) = bx^2 + 32

f(2) = b(2)^2 + 32

f(2) = 4b + 32

f(2) = 4b = -32

f(2) = b = -32/4

f(2) = b = -8

Thus;

f(-2) = -8(-2)^2 + 32

f(-2) = -8(4) + 32

f(-2) = -32 + 32

f(-2) = 0

6 0
3 years ago
Read 2 more answers
Help me!! Find the area of this figure.​
Nezavi [6.7K]

Answer:

510

Step-by-step explanation:

divide into chunks. I divided it like how you would draw the equal sign.

for top chunk, 20*8=160

for 2nd chunk, 8*25=200

for the last chunk, 15*10=150

add up 160, 200, and 150

8 0
3 years ago
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What is the longest line segment that can be drawn in a right rectangular prism that is 15cm​ long, 13cm​ wide, and 8cm​ tall?
Effectus [21]

Answer:

15cm long

Step-by-step explanation:

8 0
3 years ago
Solve for y 16y^2-25=0
Pepsi [2]

Answer:

\large\boxed{x=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}

Step-by-step explanation:

16y^2-25=0\\\\METHOD\ 1:\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\16=4^2\ \text{and}\ 25=5^2\ \text{therefore we have}\\\\4^2y^2-5^2=0\\\\(4y)^2-5^2=0\\\\(4y-5)(4y+5)+0\iff4y-5=0\ \vee\ 4y+5=0\\\\4y-5=0\qquad\text{add 5 to both sides}\\4y=5\qquad\text{divide both sides by 4}\\\boxed{y=\dfrac{5}{4}}\\\\4y+5=0\qquad\text{subtract 5 from both sides}\\4y=-5\qquad\text{divide both sides by 4}\\\boxed{x=-\dfrac{5}{4}}

METHOD\ 2:\\\\16y^2-25=0\qquad\text{add 25 to both sides}\\\\16y^2=25\qquad\text{divide both sides by 16}\\\\y^2=\dfrac{25}{16}\to y=\pm\sqrt{\dfrac{25}{26}}\\\\y=-\dfrac{\sqrt{25}}{\sqrt{16}}\ \vee\ x=\dfrac{\sqrt{25}}{\sqrt{16}}\\\\\boxed{y=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}

7 0
3 years ago
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