Rotating Q 180 degrees using the center P has the same effect as reflecting Q over the Line M
Step-by-step explanation:
Rotating Q 180 degrees using the center P has the same effect as reflecting Q over the Line M and this is because Lines L and M are perpendicular lines ( i.e. lines that meet a right angle ( 90° ).
Hence rotating Q 180 degrees form the center will be similar to reflecting Q over any of the perpendicular lines
Answer:
2/5
Step-by-step explanation:
First by looking, you have a slope going upward to the right so it is a positive slope.
Two points on the line that seem to go directly through the grid at the intersection points are ( -60, -90) and ( 40, -50).
Slope is Rise (y axis) over the Run (x axis). The numbers above have x first and y second.
So the rise is the total distance between -90 and -50 which is 40.
The run is the total distance between 40 and -60 which is a total of 100.
It takes 40 units to get back to the 0 mark on the x axis and the another 60 units to get to the -60 point.
So you slop is 40/100. You can simplify this down to 4/10 or even further to give you 2/5.
Answer:
sin(<A)
Step-by-step explanation:
For this case we represent in the complex plane numbers of the form:
a + bi
Where,
a: real part
bi: imaginary part
We represent the real part on the x axis.
We represent the imaginary part in the y axis.
Therefore, for the following numbers we have:
-3 + 8i: quadrant 2
4i: on the vertical axis
6: on the horizontal axis
5-2i: quadrant 4
