G^−m ÷ g^n
1st g^−m=1/g^m, hence g^−m ÷ g^n = (1/g^m) /(g^n)==> 1/(g^m)(g^(n)
==> 1/(g^m+n) or g^(-m-n)
Answer:
29 1/3
Step-by-step explanation:
All I did was 1760/60 and got that! I hope its right and I hope this helps!!
Answer:
Step-by-step explanation:
where is the diagram