Answer:
2.
Step-by-step explanation:
-10 divided by -5 is 2. The two negatives cancel each other out.
Answer:
5y - 6x = 8 or y = 6x/5 + 8/5
Step-by-step explanation:
let M1= gradient of line AB and M2= gradient of the second line
When two lines are perpendicular, the product of their gradients is -1
i.e, M1M2= -1
M2= -1/M1
A(2,9) and B(8,4)
gradient= (y2-y1)/(x2-x1)
M1= (4-9)/(8-2)
= -5/6
M2= -1÷ -5/6
-1 × -6/5= 6/5
Equation of the line passing through C(-3,-2)
[y-(-2)]/[x-(-3)= 6/5
(y+2)/(x+3)= 6/5
5(y+2)= 6(x+3)
5y+10=6x+18
5y= 6x + 8
y= 6x/5 + 8/5
THE ANSWER IS 13.3 BECAUSE YOU HAVE TO DIVIDE 40/3 AND GET13.3
Answer:
y=1/8x+1.25
Step-by-step explanation:
Since it's perpendicular change the slope to the opposite
You have the slope so plug it into the equation y-y1=m(x-x1)
y-(1)=(1/8)(x--2)
Answer:
i. 1.63 s
ii. The negative time cannot be used in this context
Step-by-step explanation:
i. Since h = −640t² and the rocket descends 1,690 m, h = -1,690 m (since there is a drop in height).
So, h = -640t²
t² = h/-640
t = √(- h/640)
Substituting h into the equation, we have
t = √(- h/640)
t = √[-(-1,690)/640]
t = √2.640625
t = 1.625
t ≈ 1.63 s
ii. So, the negative time cannot be used in this context because, the height drop is negative.
