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pochemuha
3 years ago
5

I need an answer please

Mathematics
2 answers:
Aloiza [94]3 years ago
8 0

Answer: 46.64

Step-by-step explanation:

Its correct trust me

Westkost [7]3 years ago
7 0

Answer:

it is C

Step-by-step explanation:

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Which sentence means Jack ate 2 ⁄ 4 of a pizza?
ale4655 [162]

what are the sentences? but 2/4, could also be 1/2 or a half

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The length of a rectangle is 16 inches ,and its area is (32+48)square inches . Factor the expression for the area .write an expr
Snezhnost [94]
Area=length*width
(32+48)=(16)*(width)
80=(16)(width)
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∠1 is decomposed into two nonoverlapping angles, ∠2 and ∠3.
Goshia [24]
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4 0
3 years ago
Half-life of Po-210 is 140 days. If the initial mass of the sample is 5
Anna35 [415]

Answer:

0.625kg

Step-by-step explanation:

we are given half-life of PO-210 and the initial mass

we want to figure out the remaining mass <u>after</u><u> </u><u>4</u><u>2</u><u>0</u><u> </u><u>days</u><u> </u>

in order to solve so we can consider the half-life formula given by

\displaystyle f(t) = a {0.5}^{t/T}

where:

  • f(t) is the remaining quantity of a substance after time t has elapsed.
  • a is the initial quantity of this substance.
  • T is the half-life

since it halves every 140 days our T is 140 and t is 420. as the initial mass of the sample is 5 our a is 5

thus substitute:

\displaystyle f(420)=5\cdot{0.5}^{420/140}

reduce fraction:

\displaystyle f(420)=5\cdot{0.5}^{3}

By using calculator we acquire:

\displaystyle f(420)=0.625

hence, the remaining sample after 420 days is 0.625 kg

4 0
3 years ago
The ages of 11 students enrolled in an on-line macroeconomics course are given in the following steam-and-leaf display:
blsea [12.9K]

Answer:

The standard deviation of the age distribution is 6.2899 years.

Step-by-step explanation:

The formula to compute the standard deviation is:

SD=\sqrt{\frac{1}{n}\sum\limits^{n}_{i=1}{(x_{i}-\bar x)^{2}}}

The data provided is:

X = {19, 19, 21, 25, 25, 28, 29, 30, 31, 32, 40}

Compute the mean of the data as follows:

\bar x=\frac{1}{n}\sum\limits^{n}_{i=1}{x_{i}}

  =\frac{1}{11}\times [19+19+21+...+40]\\\\=\frac{299}{11}\\\\=27.182

Compute the standard deviation as follows:

SD=\sqrt{\frac{1}{n}\sum\limits^{n}_{i=1}{(x_{i}-\bar x)^{2}}}

      =\sqrt{\frac{1}{11-1}\times [(19-27.182)^{2}+(19-27.182)^{2}+...+(40-27.182)^{2}]}}\\\\=\sqrt{\frac{395.6364}{10}}\\\\=6.28996\\\\\approx 6.2899

Thus, the standard deviation of the age distribution is 6.2899 years.

7 0
3 years ago
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