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yan [13]
3 years ago
7

A number is 9 more than another number. Twice the sum of the two numbers is 10. Find the two numbers.

Mathematics
2 answers:
Artemon [7]3 years ago
7 0

Answer:

7, -2

Step-by-step explanation:

we call the first number "X" and the second one "Y"

X is 9 more than Y! which means we need to add 9 to Y so it'll be equal to X. so: Y+9=X

also 2×(X+Y)=10

you can also write this down as: 2X+2Y=10

now we have:

X=Y+9

2X+2Y=10

you can now put what equals to X in the second Equation:

2(Y+9)+2Y=10 => 2Y+18+2Y=10 => 4Y=10-18 =>Y= -2

the only thing left to do is to put Y= -2 in the first equation:

X= -2+9 => X=7

erik [133]3 years ago
5 0
  • Answer:

<em>a = 7</em>

<em>b = - 2</em>

  • Step-by-step explanation:

<em>a = b + 9</em>

<em>2(a + b) = 10 => a + b = 5</em>

<em>replace a</em>

<em>(b + 9) + b = 5</em>

<em>2b = 5 - 9</em>

<em>2b = - 4</em>

<em>b = - 2</em>

<em>replace b</em>

<em>a = - 2 + 9</em>

<em>a = 7</em>

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5 = 4

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Assume the sample below is a perfectly random sample of students at a school. How much greater is the mean of the
igor_vitrenko [27]

Answer:

0.75

Step-by-step explanation:

The table is not well presented (See Attachment)

There are at least two approaches to this question

Method 1:  

Steps

1. Calculate the mean of reported heights

Mean of reported heights = (61+68+57.5+48.5+75+65+80+68+69+63)/10

Mean of reported heights = 655/10

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2. Calculate the mean of measured heights

Mean of measured heights = (62 + 68 + 56.5 + 47 + 72 + 65 + 78 + 67 + 69.5 + 62.5)/10

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Method 2: Calculate the mean of their difference

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Note that in both cases, the result is 0,75.

Hence, the reported heights at the school is 0.75 greater than the actual measured height

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