Hi, your question was incomplete hence I have attached the complete version of the question below.
Answer:
<u>5x^3 y^2</u>
Step-by-step explanation:
Using the property of the product of the exponents on the base and removing the parentheses,
(125x^9y^6)^(1/3) = (125)^(1/3) * (x^9)^(1/3) * (y^6)^(1/3)
= (125)^(1/3) * (x)^9*(1/3) * (y)^6*(1/3)
= 5 * (x)^3 * (y)^2
= 5 x^3 y^2
hence the required result is 5 x^3 y^2
The Z-score is 2.306 to three decimal places. However, the Z-test statistic value shows that it is greater than the Z-critical value, so we reject the null hypothesis
A z-score is a measurement of how often standard deviations the score obtained from a z-test is beyond or under the mean population.
From the given data information, let us find the mean and the standard deviation.
Mean (x) = 2425.6
The hypothesis testing can be computed as:
The standard deviation (σ) is:
= 1788.71
Now, the Z-test statistic is determined using the formula:
Z ≅ 2.306
Therefore, at a 0.05 level of significance, the Z-critical value is 2.306. However, since the Z-test statistic value shows that it is greater than the Z-critical value, so we reject the null hypothesis
The complete question is given as:
Using a sequencing method called "RNAseq," a researcher determines the level of FOXP2 expression in 10 different samples of lung tissue, and obtains these data:
Scientist has previously determined that FOXP2 is expressed in brain tissue at a level of 6,550. Calculate the Z-score associated with a test to see if the average expression of FOXP in her lung tissue samples is different from the levels she measured from brain tissue.
Learn more about calculating the Z-score of a test statistics here:
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