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Margaret [11]
3 years ago
10

A 45 Kg object is given a net force of 500 n what is its approximate acceleration

Physics
1 answer:
Vanyuwa [196]3 years ago
4 0
Acceleration = force / mass = 500/45 = 11.1 m/s^2
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A 0.46-kg cord is stretched between two supports, 7.2 m apart. When one support is struck by a hammer, a transverse wave travels
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Answer:

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Explanation:

given,

mass of the cord = 0.46 Kg

length of the supports = 7.2 m

time taken to travel = 0.74 s

tension in the chord = ?

using formula for tension calculation

T = \dfrac{v^2.m}{l}

v = \dfrac{l}{s}

v = \dfrac{7.2}{0.74}

v = 9.73 m/s

now, calculation of tension

T = \dfrac{9.73^2\times 0.46}{7.2}

      T = 6.0 N

The tension in the cord is equal to 6.0 N.

7 0
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Answer:

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The aluminum atom______electrons to form an ion.<br> The ion that is formed is______.
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The aluminum atom_loses_____electrons to form an ion.

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after losing 3 electrons , the ion formed is given as Al³⁺

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A machine does 1200 J of work in 1 min. What is the power developed
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Answer:

20 watts

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Big brain mode activated:

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two circular loops of wire, each containing a single turn, have the same radius of 4.0 cm and a common center. the planes of the
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The magnetic field at center of circular loops of wire is 3.78 x 10¯⁵ T.

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where B is magnetic field, μ₀ is vacuum permeability (4π×10¯⁷ H/m), I is the current and r is radius.

From the question above, we know that:

r = 4 cm = 0.04 m

I = 1.7 A

By substituting the parameter, we get

B = μ₀ . I / 2r

B = 4π×10¯⁷ . 1.7 / (2.0.04)

B = 2.67 x 10¯⁵ T

Due to the perpendicular plane of loops, the total magnetic field at center will be

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Find more on magnetic field at: brainly.com/question/7802337

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