An object takes 29.5 years to orbit the Sun. What is its average distance from the Sun?

Andrew pokes a marble, and the marble rolls down a ramp. The marble moves with speed. Which forces are acting on the marble in t

MissTica

Answer: Velocity, Gravity, and Momentum

8 0

3 years ago

Read 2 more answers

Talk to a financial planner or an insurance agent about the financial difficulties faced by people who lack adequate home and au

adelina 88 [10]

Answer:

Answered

Explanation:

There are people out there who understand the value of insurance and want adequate coverage at a cheap rates. In my opinion, these are the best clients. You don't need to sell the person on the value of insurance; they all are ready to understand it. In my opinion, it may be difficult to work with people who do not fully understand the value of insurance. These are the people who usually want necessary minimum coverage at the absolute inexpensive cost. However, when they need to make a claim that they are usually shocked to find out, feeling how they don't any coverage.

6 0

3 years ago

Which one of the following formulas is used to find the voltage of a circuit?

Sedbober [7]

D , since Voltage is one joule per coulomb

8 0

3 years ago

When a small object is launched from the surface of a fictitious planet with a speed of 52.9 m/s, its final speed when it is ver

NISA [10]

Answer:

The escape speed of the planet is 41.29 m/s.

Explanation:

Given that,

Speed = 52.9 m/s

Final speed = 32.3 m/s

We need to calculate the launched with excess kinetic energy

Using formula of kinetic energy

$K.E=\dfrac{1}{2}mv^2$

$K.E=\dfrac{1}{2}\times m\times(32.3)^2$

We need to calculate the escape speed of the planet

Using formula of kinetic energy

$\text{escape kinetic energy}=\text{launch kinetic energy}-\text{excess kinetic energy}$

$\dfrac{1}{2}mv^2=\dfrac{1}{2}mv^2-\dfrac{1}{2}mv^2$

$\dfrac{1}{2}\times v^2=\dfrac{1}{2}\times(52.9)^2-\dfrac{1}{2}\times(32.3)^2$

$v=\sqrt{2\times(\dfrac{1}{2}\times(52.9)^2-\dfrac{1}{2}\times(32.3)^2)}$

$v=41.29\ m/s$

Hence, The escape speed of the planet is 41.29 m/s.

4 0

3 years ago

An automobile has a mass of 1200 kg. what is its kinetic energy, in kj, relative to the road when traveling at a velocity of 50

snow_lady [41]

One thing you should notice. It is kind of weird. Ke has no direction so that fact that it has velocities associated with it does not matter. It becomes a scaler (something measured by amount alone).

General Formula
Ke = 1/2 m v^2
Formula for this problem
Ke = 1/2 m (v2)^2 - 1/2 m (v1)^2

Givens
m = 1200 kg
v2 = 100 km/hr = 100 km/h * [1 hour / 3600 sec] * [1000 m/ 1km] = 27.8 m/s
v1 = 50 km / hr = 13.9 m/s

Substitution and work.
================
delta Ke = 1/2 1200 (27.8)^2 - 1/2 1200 (13.9)^2
delta Ke = 463704 - 115926
delta Ke = 34778 Joules
delta Ke = 34.8 kJ

The change is 34.8 kJ which means that the vehicle gains 34.8 kJ

5 0

3 years ago