An object takes 29.5 years to orbit the Sun. What is its average distance from the Sun?

The 8 kg block is then released and accelerates to the right, toward the 2 kg block. The surface is rough and the coefficient of

natita [175]

Answer:

3.258 m/s

Explanation:

k = Spring constant = 263 N/m (Assumed, as it is not given)

x = Displacement of spring = 0.7 m (Assumed, as it is not given)

$\mu$ = Coefficient of friction = 0.4

Energy stored in spring is given by

$U=\dfrac{1}{2}kx^2\\\Rightarrow U=\dfrac{1}{2}\times 263\times 0.7^2\\\Rightarrow U=64.435\ J$

As the energy in the system is conserved we have

$\dfrac{1}{2}mv^2=U-\mu mgx\\\Rightarrow v=\sqrt{2\dfrac{U-\mu mgx}{m}}\\\Rightarrow v=\sqrt{2\dfrac{64.435-0.4\times 8\times 9.81\times 0.7}{8}}\\\Rightarrow v=3.258\ m/s$

The speed of the 8 kg block just before collision is 3.258 m/s

7 0

3 years ago

Which of the following phenomena provides evidence of electric fields in the atmosphere?

frosja888 [35]

The ground(Earth's surface) is at low potential whereas the clouds are at higher potential. Due to this potential difference, we see lightning.

7 0

3 years ago

Read 2 more answers

The gravitational field strength at a distance R from the center of moon is gR. The satellite is moved to a new circular orbit t

3241004551 [841]

Answer:

$g'=\frac{g__R}{4}$

Explanation:

Given:

gravitational field strength of moon at a distance R from its center, $g__R$

Distance of the satellite from the center of the moon, $h=2R$

<u>Now as we know that the value of gravity of any heavenly body is at height h is given as:</u>

$g'=g__{R}} \times \frac{R^2}{(2R)^2}$

$g'=\frac{g__R}{4}$

∴The gravitational field strength will become one-fourth of what it is at the surface of the moon.

6 0

4 years ago

In a lab experiment, two identical gliders on an air track are held together by a piece of string, compressing a spring between

ddd [48]

Answer:

Part a)

$v_2 = -0.300$

Part b)

Here final kinetic energy is more than the initial kinetic energy

This increase in kinetic energy is due to spring connected between them as the spring energy is converted into kinetic energy of two blocks

Explanation:

Part a)

As we know that there is no external force on the system of two gliders

So here we can use momentum conservation for two gliders

So we will have

$m_1 v_1 + m_2 v_2 = (m_1 + m_2)v_i$

$m_1 = m_2$

$1.300 + v_2 = 2(0.500)$

$v_2 = -0.300$

Part b)

now we will have

initial kinetic energy of both gliders is given as

$K_i = \frac{1}{2}(m + m)(0.500)^2$

$K_i = 0.25m$

Final kinetic energy of two gliders

$K_f = \frac{1}{2}m(0.300)^2 + \frac{1}{2}m(1.300)^2$

$K_f = 0.89 m$

so here final kinetic energy is more than the initial kinetic energy

This increase in kinetic energy is due to spring connected between them as the spring energy is converted into kinetic energy of two blocks

8 0

3 years ago

To analyze the experiment used to determine the properties of an electron. In 1909, Robert Millikan performed an experiment invo

sweet-ann [11.9K]

Answer:

C has 5 electrons

Explanation:

Given:

The data acquired from the experiment performed by Millikan:

Q_a = 3.20 x10^{-19} C

Q_b = 4.80 x10^{-19} C

Q_c = 8.00 x 10^{-19} C

Q_d = 9.60 x 10^{-19} C

Find:

How many Electrons were present in drop C

Solution:

It is known that the charge of an electron e = 1.602 *10^-19 C / electron.

Hence the number of electrons n in drop C will be:

n = Q_c / e

n = 8.00 x 10^{-19} / 1.602*10^-19

n = 4.99 = 5 electrons

Answer: The drop C contains 5 electrons.

5 0

3 years ago