Explanation:
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Answer:
166.67 N
Explanation:
Applying Pascal's principle,
Presure in the smaller piston(P') = Pressure in the bigger piston(P)
But,
Pressure = Force/Area
Pressure in the smaller piston(P') = Force applied to the smaller piston(F')/Area of the smaller piston(A')
Pressure in the bigger piston(P) = Force applied to the bigger piston(F)/Area of the bigger piston(A)
F'/A' = F/A.................. Equation 1
Make F the subject of the equation
F = F'A/A'.............. Equation 2
From the question,
Given: F' = 20 N, A = 120 cm², A' = 10 dm² = (10×100) = 1000 cm²
Substitute these values into equation 2
F = 20(1000)/120
F = 166.67 N
Answer:
The answer to your question is T2 = 580.5 °K
Explanation:
Data
Temperature 1 = T1 = 273°K
Pressure 1 = P1 = 388 kPa
Pressure 2 = P2 = 825 kPa
Temperature 2 = ?
Process
1.- Use the Gay-Lussac law
P1/T1 = P2/T2
-Solve for T2
T2 = P2T1/P1
-Substitution
T2 = (825)(273) / 388
-Simplification
T2 = 225225 / 388
-Result
T2 = 580.5 °K
Answer:
906.5 cm
Explanation:
1 m = 100 cm
9.065 m = 100 cm * 9.065 m = 906.5 cm
