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Anna007 [38]
3 years ago
10

An object takes 29.5 years to orbit the Sun. What is its average distance from the Sun?

Physics
1 answer:
KatRina [158]3 years ago
5 0

1.35 - 1.5 billion kilometers from the sun.

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The 8 kg block is then released and accelerates to the right, toward the 2 kg block. The surface is rough and the coefficient of
natita [175]

Answer:

3.258 m/s

Explanation:

k = Spring constant = 263 N/m (Assumed, as it is not given)

x = Displacement of spring = 0.7 m (Assumed, as it is not given)

\mu = Coefficient of friction = 0.4

Energy stored in spring is given by

U=\dfrac{1}{2}kx^2\\\Rightarrow U=\dfrac{1}{2}\times 263\times 0.7^2\\\Rightarrow U=64.435\ J

As the energy in the system is conserved we have

\dfrac{1}{2}mv^2=U-\mu mgx\\\Rightarrow v=\sqrt{2\dfrac{U-\mu mgx}{m}}\\\Rightarrow v=\sqrt{2\dfrac{64.435-0.4\times 8\times 9.81\times 0.7}{8}}\\\Rightarrow v=3.258\ m/s

The speed of the 8 kg block just before collision is 3.258 m/s

7 0
3 years ago
Which of the following phenomena provides evidence of electric fields in the atmosphere?
frosja888 [35]
The ground(Earth's surface) is at low potential whereas the clouds are at higher potential. Due to this potential difference, we see lightning.
7 0
3 years ago
Read 2 more answers
The gravitational field strength at a distance R from the center of moon is gR. The satellite is moved to a new circular orbit t
3241004551 [841]

Answer:

g'=\frac{g__R}{4}

Explanation:

Given:

  • gravitational field strength of moon at a distance R from its center, g__R
  • Distance of the satellite from the center of the moon, h=2R

<u>Now as we know that the value of gravity of any heavenly body is at height h is given as:</u>

g'=g__{R}} \times \frac{R^2}{(2R)^2}

g'=\frac{g__R}{4}

∴The gravitational field strength will become one-fourth of what it is at the surface of the moon.

6 0
4 years ago
In a lab experiment, two identical gliders on an air track are held together by a piece of string, compressing a spring between
ddd [48]

Answer:

Part a)

v_2 = -0.300

Part b)

Here final kinetic energy is more than the initial kinetic energy

This increase in kinetic energy is due to spring connected between them as the spring energy is converted into kinetic energy of two blocks

Explanation:

Part a)

As we know that there is no external force on the system of two gliders

So here we can use momentum conservation for two gliders

So we will have

m_1 v_1 + m_2 v_2 = (m_1 + m_2)v_i

m_1 = m_2

1.300 + v_2 = 2(0.500)

v_2 = -0.300

Part b)

now we will have

initial kinetic energy of both gliders is given as

K_i = \frac{1}{2}(m + m)(0.500)^2

K_i = 0.25m

Final kinetic energy of two gliders

K_f = \frac{1}{2}m(0.300)^2 + \frac{1}{2}m(1.300)^2

K_f = 0.89 m

so here final kinetic energy is more than the initial kinetic energy

This increase in kinetic energy is due to spring connected between them as the spring energy is converted into kinetic energy of two blocks

8 0
3 years ago
To analyze the experiment used to determine the properties of an electron. In 1909, Robert Millikan performed an experiment invo
sweet-ann [11.9K]

Answer:

C has 5 electrons

Explanation:

Given:

The data acquired from the experiment performed by Millikan:

Q_a = 3.20 x10^{-19}  C

Q_b = 4.80 x10^{-19}  C

Q_c = 8.00 x 10^{-19}  C

Q_d = 9.60 x 10^{-19}  C

Find:

How many Electrons were present in drop C

Solution:

It is known that the charge of an electron e = 1.602 *10^-19 C / electron.

Hence the number of electrons n in drop C will be:

      n = Q_c / e

      n = 8.00 x 10^{-19}  / 1.602*10^-19

      n = 4.99 = 5 electrons  

Answer: The drop C contains 5 electrons.

5 0
3 years ago
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