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3 years ago

14

What quantity measures the number of complete cycles an oscillation makes per second? A. period B. amplitude C. frequency D. for

ce

1 answer:

Free_Kalibri [48]3 years ago

8 0

Hello, there Jcparris

Your answer is going to be C. Frequency

If my answer helped please leave a thank rate 5 stars and the most important rank me braiinliest thank you and have a great day!

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One kind of baseball pitching machine works by rotating a light and stiff rigid rod about a horizontal axis until the ball is mo

Veseljchak [2.6K]

Answer:

a. ac = 1844.66 m/s²

b. Fc = 265.63 N

Explanation:

a.

The centripetal acceleration of the ball is given as follows:

ac = v²/r

where,

ac = centripetal acceleration = ?

v = speed of ball = (87 mph)(1 h/ 3600 s)(1609.34 m / 1 mile) = 38.9 m/s

r = radius of path = 82 cm = 0.82 m

Therefore,

ac = (38.9 m/s)²/0.82 m

<u>ac = 1844.66 m/s²</u>

<u></u>

b.

The centripetal force is given as:

Fc = (m)(ac)

Fc = (0.144 kg)(1844.66 m/s²)

<u>Fc = 265.63 N</u>

6 0

3 years ago

Un bombero alejado d = 31.0 m de un edificio en llamas dirige un chorro de agua desde una manguera contra incendios a nivel del

Mila [183]

Answer:

El chorro golpea el edificio a una altura de 15.943 metros con respecto al suelo.

Explanation:

El chorro de agua exhibe un movimiento parabólico, dado que este tiene una inclinación inicial y la única aceleración es debida a la gravitación terrestre. Las ecuaciones cinemáticas que modelan el fenómeno son:

Distancia horizontal (en metros)

$x = x_{o} + v_{o}\cdot t \cdot \cos \theta$

Donde:

$x_{o}$ - Posición horizontal inicial, medida en metros.

$t$ - Tiempo, medido en segundos.

$v_{o}$ - Velocidad inicial, medida en metros por segundo.

$\theta$ - Angulo de inclinación del chorro de agua, medido en grados sexagesimales.

Distancia vertical (en metros)

$y = y_{o} + v_{o}\cdot t \cdot \sin \theta + \frac{1}{2}\cdot g \cdot t^{2}$

Donde:

$y_{o}$ - Posición vertical inicial, medida en metros.

$g$ - Constante gravitacional, medida en metros por segundo al cuadrado.

Partiendo de la primera ecuación, se despeja el tiempo:

$t = \frac{x - x_{o}}{v_{o}\cdot \cos \theta}$

Si $x = 31\,m$ , $x_{o} = 0\,m$ , $v_{o} = 40\,\frac{m}{s}$ and $\theta = 33^{\circ}$ , entonces:

$t = \frac{31\,m-0\,m}{\left(40\,\frac{m}{s} \right)\cdot \cos 33^{\circ}}$

$t = 0.924\,s$

La altura máxima se calcula por sustitución directa de términos en la segunda ecuación. Si $y_{o} = 0\,m$ , $v_{o} = 40\,\frac{m}{s}$ , $t = 0.924\,s$ y $g = -9.807\,\frac{m}{s^{2}}$ , entonces:

$y = 0\,m + \left(40\,\frac{m}{s} \right)\cdot (0.924\,s)\cdot \sin 33^{\circ} + \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right) \cdot (0.924\,s)^{2}$

$y = 15.943\,m$

El chorro golpea el edificio a una altura de 15.943 metros con respecto al suelo.

3 0

3 years ago

Which of the following organs are found in the

Hatshy [7]

Answer:

small intestine, tongue and large intestine

Explanation:

The GI tract is a series of hollow organs joined in a long, twisting tube from the mouth to the anus. The hollow organs that make up the GI tract are the mouth, esophagus, stomach, small intestine, large intestine, and anus. The liver, pancreas, and gallbladder are the solid organs of the digestive system.

3 0

3 years ago

What are 2 factors affect air resistance on an object

inessss [21]

friction and the density of the air.

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=See%20%5C%3A%20%20Attachment.%20%20%5C%3A%20" id="TexFormula1" title="See \: Attachment. \:

Tcecarenko [31]

So acceleration = (final velocity - initial velocity)/time

So (fv-iv)/t=a

(45-110)/4.5

Gives you (-130/9)km/h^2

You may have to convert the SI units so just follow my steps and change what must be changed

4 0

3 years ago

Read 2 more answers