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Romashka-Z-Leto [24]
3 years ago
13

What sequence of transformations, when applied to △XYZ , shows that △XYZ is similar to △X′Y′Z′ ?

Mathematics
2 answers:
jek_recluse [69]3 years ago
8 0

Answer:

dilation with respect to the origin by a scale factor of 2 followed by a translation of 4 units down

Step-by-step explanation:

stiks02 [169]3 years ago
4 0
The coordinates of Δxyz ⇒⇒ x(1,1)     y(2,3)    z(3,2)
The coordinates of Δx'y'z' ⇒⇒ x'(2,-2)   y'(4,2)    z'(6,0)

1. Applying the transformation of the first sentence on Δxyz
The results are ⇒⇒⇒ (2,-2)   (4,2)    (6,0)

2. Applying the transformation of the second sentence on Δxyz
The results are ⇒⇒⇒ (12,14)   (24,38)    (36,28)

3. Applying the transformation of the third sentence on Δxyz
The results are ⇒⇒⇒ (12,-36)   (24,-12)    (36,-24)

4. Applying the transformation of the fourth sentence on Δxyz
The results are ⇒⇒⇒ (2,-6)   (4,-2)    (6,-4)

By comparing the results obtained with the coordinates of Δx'y'z'
So, the correct answer is the first sentence.
<span>dilation with respect to the origin by a scale factor of 2 followed by a translation of 4 units down</span>








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Equation of line 1  is 3 X - 4 Y = 20

Equation of line 2 is 3 X  + 4 Y = 20

Step-by-step explanation:

Given co ordinates of points as,

( -4 , 8)  and (0 , 5)

From the given two points we can determine the slop of a line

I. e slop (m) = \frac{(y2 - y1)}{(x2 - x1)}

Or,           m  = \frac{(5 - 8)}{(0 + 4)}

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Now equations of line can be written as ,

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<u>At points ( -4 , 8)</u>

Y - 8   = \frac{(-3)}{(4)} (X + 4)

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Y - 5   = \frac{(-3)}{(4)} ( X - 0)

So, Equation of line 2 is 3 X  + 4 Y = 20

Hence Equation of line 1  is 3 X - 4 Y = 20  and Equation of line 2 is 3 X  + 4 Y = 20   Answer

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Hope it helps
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