Answer:
The Sum Of The Integers From -6 To 58 is <u>1690.</u>
Step-by-step explanation:
Given,
We have to find out the sum of integers from -6 To 58.
Firstly we will find out the total number of terms that is 'n'.
Here 
Now we use the formula of A.P.
On substituting the values, we get;
So there are 65 terms in between -6 To 58.
That means we have to find the sum of 65 terms in between -6 To 58.
Now we use the formula of Sum of n_terms.
On substituting the values, we get;
Hence The Sum Of The Integers From -6 To 58 is <u>1690.</u>
The number of permutations of the 4 different letters, taken two at a time, is given by:
I think the answer to you question is 35 i might be wrong tho but it may work.
Answer:
A
Step-by-step explanation:
7x+9x+4x+8+5=20x+13
20+13.
Hope this helps :D
(2x + 3y = 12) x (-2)
(4x - 3y = 6) x 1
-4x - 6y = -24
4x - 3y = 6
You can cancel out the x values by adding the two equations together.
(-4x + 4x) + (-6y - 3y) = (-24 + 6)
-9y = -18
y = 2
Solve for x now...
4x - 3(2) = 6
4x - 6 = 6
4x = 12
x = 3
Check... (x = 3, y = 2)
2(3) + 3(2) = 12
6 + 6 = 12
12 = 12 <- this works!
4(3) - 3(2) = 6
12 - 6 = 6
6 = 6 <- this works!
