What is the geometrick mean of 27 and 8 with the pothagereom theorem

Mathematics

2 answers:

enyata [817]2 years ago

5 0

Answer:

x = 6√6

Step-by-step explanation:

27/x = x/8

x² = 27 × 8

x = √(27 × 8)

x = √(9 × 4 × 6)

x = 3 × 2 × √6

x = 6√6

Kruka [31]2 years ago

5 0

Answer:

The geometric mean of 27 and 8 is $6\sqrt{6}$ or about 14.697

Step-by-step explanation:

The geometric mean is $( \prod_{i=1}^{n} x_{i})^{\frac{1}{n}}=\sqrt[n]{x_1x_2 \cdot\: \cdot \:\cdot x_n}$ where $n$ is the number of values and $x_i$ are the values to average. Thus, your geometric mean is $\sqrt{27*8}=\sqrt{216}=6\sqrt{6}\approx14.697$

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