What is the equation of the line that passes through the point (8,-2) and has an undefined slope?

Mathematics

1 answer:

Aleksandr-060686 [28]2 years ago

3 0

Answer:

x = 8

Step-by-step explanation:

A line with an undefined slope is a vertical line parallel to the y- axis, with equation

x = c ( c is the value of the x- coordinates the line passes through )

The line passes through (8, - 2) with x- coordinate 8 , thus

x = 8 ← equation of line

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259 Students go on a field trip. There are 19 vehicles, some vans and some buses.

Sunny_sXe [5.5K]

Answer:

12 vans

7 Buses

Step-by-step explanation:

I tried multiple versions but I finally got it right.

Since the buses can hold 25 students at a time I multiplied it by 7.

7 x 25 = 175

Then you'll need to find the remainder.

259-175 = 84

This number would be used to find the students going in the van

84/7= 12

So in total there would be 12 vans

and 7 buses

I hope this helps

5 0

3 years ago

Find an equation of the plane consisting of all points that are equidistant from (-3, 5, -4) and (-5, 0, 4), and having -2 as th

Firdavs [7]

Answer:

-2x-5y+8z+4.5=0

Step-by-step explanation:

Let (x,y,z) be the coordinates of the point lying on the needed plane. This point is equidistant from the points (-3, 5, -4) and (-5, 0, 4), so

$d_1=\sqrt{(x-(-3))^2+(y-5)^2+(z-(-4))^2}=\sqrt{(x+3)^2+(y-5)^2+(z+4)^2}\\ \\d_2=\sqrt{(x-(-5))^2+(y-0)^2+(z-4)^2}=\sqrt{(x+5)^2+y^2+(z-4)^2}\\ \\d_1=d_2\Rightarrow \sqrt{(x+3)^2+(y-5)^2+(z+4)^2}=\sqrt{(x+5)^2+y^2+(z-4)^2}\\ \\(x+3)^2+(y-5)^2+(z+4)^2=(x+5)^2+y^2+(z-4)^2\\ \\x^2+6x+9+y^2-10y+25+z^2+8z+16=x^2+10x+25+y^2+z^2-8z+16\\ \\-4x-10y+16z+9=0\\ \\-2x-5y+8z+4.5=0$