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svp [43]
3 years ago
8

What is the equation of the line that passes through the point (8,-2) and has an undefined slope?

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
3 0

Answer:

x = 8

Step-by-step explanation:

A line with an undefined slope is a vertical line parallel to the y- axis, with equation

x = c ( c is the value of the x- coordinates the line passes through )

The line passes through (8, - 2) with x- coordinate 8 , thus

x = 8 ← equation of line

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A circle has a circumference of 18. It has an arc of length 6. What is the central angle of the arc, in degrees?
nadya68 [22]
Circumference: 2πr C=18 so r= 18/2π= 9π

Arc length = rθ 6=(9π)θ θ=6/9π

Convert to degrees by multiplying by 180/π

6/9π x 180/π = 120 degrees
4 0
3 years ago
A circle with radius of \greenD{5\,\text{cm}}5cmstart color #1fab54, 5, start text, c, m, end text, end color #1fab54 sits insid
Marat540 [252]

Answer:

The area of the shaded region is 42.50 cm².

Step-by-step explanation:

Consider the figure below.

The radius of the circle is, <em>r</em> = 5 cm.

The sides of the rectangle are:

<em>l</em> = 11 cm

<em>b</em> = 11 cm.

Compute the area of the shaded region as follows:

Area of the shaded region = Area of rectangle - Area of circle

                                            =[l\times b]-[\pi r^{2}]\\\\=[11\times 11]-[3.14\times 5\times 5]\\\\=121-78.50\\\\=42.50

Thus, the area of the shaded region is 42.50 cm².

7 0
3 years ago
Read 2 more answers
Using the formula in model 1, choose the correct answers for the new balance and the amount of interest earned in the following
Sedbober [7]
A=p(1+r)^t
A=650×(1+0.08)^(14)
A=1,909.18
Interest earned=a-p=1909.18-650=1,259.18
8 0
3 years ago
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How do I solve this problem(3x-4y)-(6x-28y)
Tema [17]

Answer:

3x-4y-6x+28y

-3x-6x-4y+28y

-9x+24y

Step-by-step explanation:

5 0
3 years ago
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The mean time required to repair breakdowns of a certain copying machine is 93 minutes. The company which manufactures the machi
Sonja [21]

Answer:

t=\frac{88.8-93}{\frac{26.6}{\sqrt{73}}}=-1.349    

p_v =P(t_{(72)}  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can't concluce that the true mean is less than 93 min at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=88.8 represent the sample mean

s=26.6 represent the sample standard deviation for the sample  

n=73 sample size  

\mu_o =93 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean i lower than 93 min, the system of hypothesis would be:  

Null hypothesis:\mu \geq 93  

Alternative hypothesis:\mu < 93  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{88.8-93}{\frac{26.6}{\sqrt{73}}}=-1.349    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=73-1=72  

Since is a one side test the p value would be:  

p_v =P(t_{(72)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can't concluce that the true mean is less than 93 min at 5% of signficance.  

5 0
3 years ago
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