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son4ous [18]
3 years ago
13

A black bear has a tail 190 mm long.How many cm is that?

Mathematics
2 answers:
GarryVolchara [31]3 years ago
7 0

Answer:19

Step-by-step explanation:

Divide 190 by 10

melomori [17]3 years ago
5 0

Answer:

The black bear's tail is 19 centimetres long

Step-by-step explanation:

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Select the correct answer.
malfutka [58]

Answer:

B

Step-by-step explanation:

B

x - 4 squared provides 2 real zeros that are the same. These two are not distinct.

The other two come from x^2 - 7x + 10 which has a discriminate of

sqrt(7^2 - 4*1*10) = sqrt(9) = +/- 3 leading to something real and different.

6 0
3 years ago
I NEED HELP PLZ ( WILL GIVE BRAINLYIST) ( NO LINKS)
AlladinOne [14]

9514 1404 393

Answer:

  66 cm²

Step-by-step explanation:

The area of the polygon is the sum of the areas of the triangle and the rectangle it sits on. The dimensions of the triangle can be found by examining the top/bottom dimensions shown and the left/right dimensions shown.

The width (base) of the triangle is the difference between the lengths of the bottom and top horizontal lines: (12 -9) cm = 3 cm.

The height of the triangle is the difference between the lengths of the left and right sides of the figure: (9 -5) cm = 4 cm.

The dimensions of the rectangle are shown a the bottom and the left sides of the figure.

  triangle area = 1/2bh = 1/2(3 cm)(4 cm) = 6 cm²

  rectangle area = LW = (12 cm)(5 cm) = 60 cm²

Total polygon area = 6 cm² + 60 cm² = 66 cm²

4 0
3 years ago
For g(x) = 1/3x – 2, find the value of x for which g(x) = -4​
kirill [66]
Answer is attached ! Hope it helps

5 0
2 years ago
What is the gcf of 24a^3c and 3a?
Archy [21]
24a^3c = 3a(8a^2c)

3a = 3a(1)

\text {GCF = }3a
6 0
3 years ago
A ladder 10 ft long rests against a vertical wall. If the bottom of the ladder slides away from the wall at a rate of 0.8 ft/s,
shusha [124]

Answer:

-0.133 radians/s is the angle between the ladder and the ground changing when the bottom of the ladder is 8 ft from the wall.

Step-by-step explanation:

Let

x= distance between the wall and ladder

Ф = angle between the ladder and ground

The rate of change is: dx/dt = 0.8 ft/s

We need to find dФ/dt when x = 8 ft/s

From the triangle in the figure we see that:

cos Ф = x/10

=> x = 10 cosФ

Now, the rate of change will be

d(x)/dt = d/dt (10cosФ)

dx/dt = -10 sin Ф dФ/dt

dx/dt = 0.8 (given)

to find dФ/dt

we need to find sin Ф when x = 8

By Pythagoras theorem

(hypotenuse)^2 = (Perpendicular)^2+(base)^2

(10)^2 = (8)^2+ (Perpendicular)^2

100 = 64 +  (Perpendicular)^2

=>  (Perpendicular)^2 = 100-64

(Perpendicular)^2 = 36

Perpendicular = 6

sin Ф = Perpendicular/hypotenuse

sin Ф = 6/10 = 3/5

Putting values in:

dx/dt = -10 sin Ф dФ/dt

0.8 = -10(3/5) dФ/dt

0.8 = -6 dФ/dt

=> dФ/dt = 0.8 / -6

dФ/dt = - 0.133 radians/s

So, -0.133 radians/s is the angle between the ladder and the ground changing when the bottom of the ladder is 8 ft from the wall.

3 0
3 years ago
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