Answer:
In: 5, 4, 2, 3, 1, and 10.
Out: 40, 32, 16, 24, 8, and 80
Step-by-step explanation:
The first step you should do is to take notice of the pairs that have their "in" and "out" both answered.
The second step is to find out what you must multiply the "in" by to get the "out". In this answer, you must multiply the "in" by 8 to get the "out".
The third step is to do the same thing for all of the values until the chart is completely filled with values.
The fourth step is to check your work!
If you have any questions, please let me know!
Answer:
![\displaystyle A _{ \text{trapezoid}} = 70 {m}^{2}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20A%20_%7B%20%5Ctext%7Btrapezoid%7D%7D%20%3D%20%2070%20%7Bm%7D%5E%7B2%7D%20)
Step-by-step explanation:
we are given a trapezoid
we want to figure out the area
remember that,
![\displaystyle A _{ \text{trapezoid}} = \frac{a + b}{2} h](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20A%20_%7B%20%5Ctext%7Btrapezoid%7D%7D%20%3D%20%20%5Cfrac%7Ba%20%2B%20b%7D%7B2%7D%20h)
where a and b represent the parallel lines and h represents the height
we get from the pic that a and b are 5 and 15 respectively and h is 7
so substitute:
![\displaystyle A _{ \text{trapezoid}} = \frac{5 + 15}{2} \times 7](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20A%20_%7B%20%5Ctext%7Btrapezoid%7D%7D%20%3D%20%20%5Cfrac%7B5%20%2B%2015%7D%7B2%7D%20%5Ctimes%20%207)
simplify addition:
![\displaystyle A _{ \text{trapezoid}} = \frac{20}{2} \times 7](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20A%20_%7B%20%5Ctext%7Btrapezoid%7D%7D%20%3D%20%20%5Cfrac%7B20%7D%7B2%7D%20%5Ctimes%20%207)
simplify division:
![\displaystyle A _{ \text{trapezoid}} = 10\times 7](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20A%20_%7B%20%5Ctext%7Btrapezoid%7D%7D%20%3D%20%2010%5Ctimes%20%207)
simplify multiplication:
![\displaystyle A _{ \text{trapezoid}} = 70](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20A%20_%7B%20%5Ctext%7Btrapezoid%7D%7D%20%3D%20%2070)
since we multiply two same units we of course have to use square unit
hence,
![\displaystyle A _{ \text{trapezoid}} = 70 {m}^{2}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20A%20_%7B%20%5Ctext%7Btrapezoid%7D%7D%20%3D%20%2070%20%7Bm%7D%5E%7B2%7D%20)
What do you mean about that?
Start off by combining like terms on the LHS (the terms with x in them).
So we get
![\frac{-1}{3}x+2x= \frac{-1}{3}x+ \frac{6}{3}x= \frac{-5}{3}x](https://tex.z-dn.net/?f=%20%5Cfrac%7B-1%7D%7B3%7Dx%2B2x%3D%20%5Cfrac%7B-1%7D%7B3%7Dx%2B%20%5Cfrac%7B6%7D%7B3%7Dx%3D%20%5Cfrac%7B-5%7D%7B3%7Dx%20%20%20)
Replacing this result with what we had before on the LHS, we get
![\frac{-5}{3}x=3 \frac{3}{4}= \frac{9}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B-5%7D%7B3%7Dx%3D3%20%5Cfrac%7B3%7D%7B4%7D%3D%20%5Cfrac%7B9%7D%7B4%7D%20%20%20)
⇒Solve for x (divide both sides
![\frac{-5}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B-5%7D%7B3%7D%20)
)
⇒Don't forget about reciprocity rules when dividing. This is the same as multiplying both sides by
![\frac{3}{-5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B-5%7D%20)
⇒
![x= \frac{9}{4}( \frac{3}{-5}) ](https://tex.z-dn.net/?f=x%3D%20%5Cfrac%7B9%7D%7B4%7D%28%20%5Cfrac%7B3%7D%7B-5%7D%29%0A%20%20)
⇒
![x= -\frac{27}{20}=-1\frac{7}{20}](https://tex.z-dn.net/?f=x%3D%20-%5Cfrac%7B27%7D%7B20%7D%3D-1%5Cfrac%7B7%7D%7B20%7D)
***This is a proper fraction
Answer:
D. A rectangle and an isosceles triangle
Step-by-step explanation:
In the figure attached, the sign is shown. There we can see an arrow, which can be decomposed into a rectangle (on the left of the figure) and an isosceles triangle (on the right of the figure)