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lara [203]
2 years ago
13

A room is 3 3/4 m long and 4 2/3 m wide. What is the area of the room?​

Mathematics
1 answer:
ziro4ka [17]2 years ago
4 0

Answer:

17.5 m

Step-by-step explanation:

3.75 x 4.667 etc.

17.5

(I used a calculator)

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Write an equation of the line that passes through (2,−5) and is parallel to the line 2y=3x+10
LenaWriter [7]

Step-by-step explanation:

Divide two on both sides to get rid of it and the make the equation in the form y = mx + c

\frac{2}{2} y = \frac{3}{2} x +  \frac{10}{2}

y = 3/2x + 5

since both lines are parallel they must have the same gradient which is 3/2

y = 3/2x + c

All you have to do now is to replace x and y with (2, -5) to find c

x = 2

y = -5

-5 = 3/2 × 2 + c

-5 = 3 + c

c = -5-3

c = -8

y  = \frac{3}{2} x  - 8

8 0
2 years ago
Evaluate the expression below when x = 4, y = 5<br><br> 3(y-x) + 4y
likoan [24]

Answer:

23

Step-by-step explanation:

Brackets go first, 5 (y) - 4 (x) = 1. Now, 3 x 1 = 3, you do this because of the 3 next to the brackets. Now add them together.

4 0
3 years ago
Callie read for 4 hours last week. Luis read 6 times as long. Write an equation to show how long Luis read.
zysi [14]

Answer: 24

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7 0
3 years ago
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Simplify f+g / f-g when f(x)= x-4 / x+9 and g(x)= x-9 / x+4
steposvetlana [31]

f(x)=\dfrac{x-4}{x+9};\ g(x)=\dfrac{x-9}{x+4}\\\\f(x)+g(x)=\dfrac{x-4}{x+9}+\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)+(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2+x^2-9^2}{(x+9)(x+4)}=\dfrac{2x^2-16-81}{(x+9)(x+4)}=\dfrac{2x^2-97}{(x+9)(x+4)}\\\\f(x)-g(x)=\dfrac{x-4}{x+9}-\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)-(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2-(x^2-9^2)}{(x+9)(x+4)}=\dfrac{x^2-16-x^2+81}{(x+9)(x+4)}=\dfrac{65}{(x+9)(x+4)}


\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}

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3 years ago
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