Answer:
cos3x+tan3x=0
⟹cos3x=−tan3x
⟹cos3x=−sin3xcos3x
⟹cos23x=−sin3x
⟹1−sin23x=−sin3x
⟹sin23x−sin3x−1=0
This is a quadratic equation in sin3x.
sin3x=−(−1)±(−1)2−4×1×(−1)−−−−−−−−−−−−−−−−−√2×1
sin3x=1±5–√2
If x takes real values, the upper sign must be rejected.
sin3x=1−5–√2
⟹3x=nπ+(−1)nsin−11−5–√2
⟹x=13[nπ+(−1)nsin−11−5–√2]
Step-by-step explanation:
Hope this kind of helps
Answer:
53
Step-by-step explanation:
To evaluate 6x + 11, we must substitute the value of x.
Since we know that x = 7, it is easier to evaluate the expression;
6x + 11
6(7) + 11
Since 6 is outside the parenthesis, we must multiply everything inside the parenthesis by 6;
6(7) + 11
42 + 11
When you add the two numbers you get:
53
Look at the coefficient of x (the slope).
Is -2 positive or negative?
Since -2 is negative, The slope is negative.
Answer:
around 1.67 inches
Step-by-step explanation:
We have to divide 1.25 inches by 0.75 inches to get the scale factor.
To find the area of the circle, you will use the formula for finding area of any circle.
The radius is half the diameter.
A = pi x r^2
3.14 x 13^2
A = 530.66 square units
The area is 530.66 square units.
