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Novay_Z [31]
3 years ago
5

Literally pls help me like literally pls i need help pls

Mathematics
1 answer:
jarptica [38.1K]3 years ago
3 0

Answer:

2\16

Step-by-step explanation:

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Write down the value of the 7 in the number 5709.​
Dovator [93]

Answer:

700

Step-by-step explanation:

The 9 = 9

The 0 = 0

The 7 = 700

The 5 = 5000

8 0
3 years ago
Help me anyone please
alexandr402 [8]
Question #1: Abby ended her walk at school.

Question #2: Abby and Bryan walk 9 blocks after school together to go to the grocery store and the park. After they leave the park, Bryan has to walk 5 blocks, and Abby has to walk 9 blocks to get home. Therefore Abby has to walk 4 more blocks than Bryan does.

Answer: 4 Blocks.
7 0
4 years ago
Evaluate f(2) for the function f(x) = 3x² + 2x - 5.
Softa [21]

Answer:

f(2)= 11

Step-by-step explanation:

you have to substitute 2 for every x you see:

                       f(x) = 3x² + 2x - 5

                       f(2)= 3(2)^2+2(2)-5

                       f(2)= 11

6 0
3 years ago
$1876 per month for 12 months<br> A) $22,512<br> B) $225.12<br> c) $1888<br> D) None of these
insens350 [35]

Answer:

The answer is A

Step-by-step explanation:

We need to multiply 1876 by 12. 1876 * 12 = 22, 512. That's our answer

5 0
3 years ago
2 taps A and B can fill a swimming pool in 3 hours. If turned on alone, it takes tap A 5 hours less than tap B to fill the same
vazorg [7]

Answer:

Tap A will take 2 hours and tap B will take 6 hours to fill the tank when turned on alone.

Step-by-step explanation:

Let tap B fills the pool alone in the time = x hours

So in one hour part of pool will be filled = \frac{1}{x}

Another tap A when turned on, it takes time to fill the pool = x-5 hours

So in one hour part of the same pool filled = \frac{1}{x-5}

Now both the taps A and B are turned on then time taken to fill the pool = 3 hours.

Part of the pool filled in one hour by both the taps = \frac{1}{3}

Now we form an equation

Part of pool filled in one hour by tap A + Part of pool filled in one hour by tap B = Part of pool filled in one hour by both the taps when turned on

\frac{1}{(x-5)}+\frac{1}{x}=\frac{1}{3}

\frac{x-5+1}{x(x-5)}=\frac{1}{3}

\frac{x-4}{x(x-5)}=\frac{1}{3}

3(x - 4) = x(x - 5)

x² -5x = 3x - 12

x² - 8x + 12 = 0

x² - 6x - 2x + 12 = 0

x(x - 6) - 2(x - 6) = 0

(x -2)(x - 6) = 0

x = 2, 6 hours

We will take higher value of x as x = 6 hours for tap B.

Time taken by tap A = 6 - 4 = 2 hours.

Therefore, Tap A will take 2 hours and tap B will take 6 hours to fill the tank when turned on alone.

4 0
3 years ago
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