Not sure if you mean to ask for the first order partial derivatives, one wrt x and the other wrt y, or the second order partial derivative, first wrt x then wrt y. I'll assume the former.


Or, if you actually did want the second order derivative,
![\dfrac{\partial^2}{\partial y\partial x}(2x+3y)^{10}=\dfrac\partial{\partial y}\left[20(2x+3y)^9\right]=180(2x+3y)^8\times3=540(2x+3y)^8](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cpartial%5E2%7D%7B%5Cpartial%20y%5Cpartial%20x%7D%282x%2B3y%29%5E%7B10%7D%3D%5Cdfrac%5Cpartial%7B%5Cpartial%20y%7D%5Cleft%5B20%282x%2B3y%29%5E9%5Cright%5D%3D180%282x%2B3y%29%5E8%5Ctimes3%3D540%282x%2B3y%29%5E8)
and in case you meant the other way around, no need to compute that, as

by Schwarz' theorem (the partial derivatives are guaranteed to be continuous because

is a polynomial).
Answer:
1) sarah has $100 in her bank account after 5 weeks ans Emily has $95, so Sarah has more.
2)After 6 weeks they will both have $110
Step-by-step explanation:
Answer:
Let w be the width. Then the length is 2w-4. So:
w(2w-4)=96
2w²-4w-96=0
w²-2w-48=0
(w-8)(w+6)=0
w=8 or -6
Throwing out the negative value for w, we get a width of 8 yds, and a length of 12 yds. ☺☺☺☺