vi is going in the positive direction (up). (That's my choice). a (acceleration) is going in the minus direction (down). The directions could be reversed.
Givens
vi = 160 ft/s
vf = 0 (the rocket stops at the maximum height.)
a = - 9.81 m/s
t = ????
Remark
YOu have 4 parameters between the givens and what you want to solve. Only 1 equation will relate those 4. Always always list your givens with these problems so you can pick the right equation.
Equation
a = (vf - vi)/t
Solve
- 32 = (0 - 160)/t Multiply both sides by t
-32 * t = - 160 Divide by -32
t = - 160/-32
t = 5
You will also need to solve for the height to answer part B
t = 5
vi = 160 m/s
a = - 32
d = ???
d = vi*t + 1/2 a t^2
d = 160*5 + 1/2 * - 32 * 5^2
d = 800 - 400
d = 400 feet
Part B
You are at the maximum height. vi is 0 this time because you are starting to descend.
vi = 0
a = 32 m/s^2
d = 400 feet
t = ??
formula
d = vi*t + 1/2 a t^2
400 = 0 + 1/2 * 32 * t^2
400 = 16 * t^2
400/16 = t^2
t^2 = 25
t = 5 sec
The free fall takes the same amount of time to come down as it did to go up. Sort of an amazing result.
F(-5)=3(-5)+4=-11
g(-2)=4(-2)^2+2=18
The area is 289.22 units squared
Answer:
23°
Step-by-step explanation:
Step 1:
< GEC + < ECG + < CGE = Δ ECG Sum of a Δ
Step 2:
< IGF = < GCE Corresponding ∠ 's
Step 3:
14° + 180° - 4x + 78° = 180° Substitution
Step 4:
272° - 4x = 180° Add / Algebra
Step 5:
- 4x = - 92 Subtract 272° on both sides
Step 6:
- 92 ÷ - 4 Divide
Answer:
x = 23°
Hope This Helps :)
