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cestrela7 [59]
3 years ago
12

The distance between two cities on a map is 3.5 centimeters. The map uses a scale in which 1 centimeter represents 20 kilometers

. What is the actual distance between these two cities in kilometers?
Mathematics
2 answers:
zhenek [66]3 years ago
8 0
1 cm = 20 km

so 3.5 cm would equal : 3.5 * 20 = 70 km <==
11111nata11111 [884]3 years ago
3 0
70!km is the right answer
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Grandma's soup company packages tomato soup in cylindrical cans that have a base diameter of 8 centimeters and a height of 10 ce
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Answer

i would think 2 centimeter

Step-by-step explanation:

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nydimaria [60]
Answer is 0= -2

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2 years ago
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If you could help me on all of them you a live saver
PtichkaEL [24]

Answer:

(1.37) AUB = { 1,2,3,4,5,6}

(1.38) AUC = { 1,2,3,4,5 }

(1.39)BUC = { 1,2,3,4,5,6}

(1.40) { 2,4 }

(1.41) { 1,3,5 }

(1.42) { phi }

(1.43) AU(BUC) = { 1,2,3,4,5,6 }

(1.44) { phi }

(1.45) {1,2,3,4,5}

(1.46) { 1,2,3,4,5 }

\huge\underline\red{Hope\:that\:helps}

8 0
3 years ago
4(2x−3)=4(2x)−4(3) what is the proptery
Nikitich [7]

9514 1404 393

Answer:

  distributive property

Step-by-step explanation:

The <em>distributive property</em> of multiplication over addition lets you expand the product in the manner shown.

4 0
3 years ago
What is the partial fraction decomposition of StartFraction 8 x + 19 Over (x + 8) (x minus 1) EndFraction? StartFraction 3 Over
hoa [83]

The partial fraction decomposition is \frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}

<h3>How to determine the decomposition?</h3>

The fraction is given as:

\frac{8x + 19}{(x + 8)(x - 1)}

Split the fraction as follows:

\frac{8x + 19}{(x + 8)(x - 1)} = \frac{A}{x + 8} + \frac{B}{x - 1}

Take the LCM

\frac{8x + 19}{(x + 8)(x - 1)} = \frac{Ax -A + Bx + 8B}{(x + 8)(x -1)}

Cancel the common factors

8x + 19 = Ax - A + Bx + 8B

By comparison, we have:

Ax + Bx = 8x

-A + 8B = 19

This gives

A + B = 8

-A + 8B = 19

Add both equations

9B = 27

Divide by 9

B = 3

Substitute B = 3 in A + B = 8

A + 3 = 8

Solve for A

A = 5

So, we have:

\frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}

Hence, the partial fraction decomposition is \frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}

Read more about partial fraction at:

brainly.com/question/12783868

#SPJ1

6 0
2 years ago
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