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3 years ago

May someone please help me with the equation? I would be so very thankful.

Mathematics

1 answer:

Masteriza [31]3 years ago

3 0

$\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] ~\dotfill$

$\bf \cfrac{4(3x^2y^4)^3}{(2x^3y^5)^4}\implies \cfrac{4(3^3x^{2\cdot 3}y^{4\cdot 3})}{(2^4x^{3\cdot 4}y^{5\cdot 4})}\implies \cfrac{4(27)x^6y^{12}}{16x^{12}y^{20}}\implies \cfrac{108x^6y^{12}}{16x^{12}y^{20}} \\\\\\ \cfrac{108}{16x^{12}x^{-6}y^{20}y^{-12}}\implies \cfrac{108}{16x^{12-6}y^{20-12}}\implies \cfrac{27}{4x^6 y^8}$

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Solve for X 121 +7< -11 OR 5x- 8 > 40

Trava [24]

Answer:

x > 48/5 the first one is false

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3 years ago

Factorise mx+cx+my+cy With steps!!! x=algebra x

avanturin [10]

Step-by-step explanation:

Hey there!

While factorising you remember to make it take common in most of the expression.

Here;

=mx+cx+my+cy

Take common 'x' in "mx+cx" and 'y' in my + cy.

= x(m+c) + y(m+c)

Now, "(m+c)" common again.

= (m+c) (x+y)

Therefore the factorized form of the expression in (m+c)(x+y).

Hope it helps...

6 0

3 years ago

Read 2 more answers

You work in a chemical lab. Last quarter, you successfully completed an average of about 5 chemical analyses per day. This quart

Kryger [21]

Answer: 60%

Step-by-step explanation:

Since, According to the question, Last quarter, we successfully completed an average of about 5 chemical analyses per day.

Therefore initially our average = 5 chemical analyses per day.

Again, From the question, This quarter, we have increased this average to about 8 per day.

Therefore New average =chemical analyses 8 per day

Thus, Percentage change in the average = (Initial average - New average)×100/ initial average

= $\frac{8-5}{5} \times 100$

= $\frac{3}{5} \times 100$

= 60 %

Therefore, Percentage change in the average=60 %

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3 years ago

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What is the midpoints of a segment whose endpoints are (-3, 8) and (7, -2) ?

Sidana [21]

$M = (\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$
$M = (\frac{7 - (-3)}{2}, \frac{-2 + 8}{2})$
$M = (\frac{7 - 3}{2}, \frac{6}{2})$
$M = (\frac{4}{2}, 3)$
$M = (2, 3)$

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3 years ago

HELP!!!!! ASAP PLEASE!!!!!!!!!!

Nataly_w [17]

Answer:

Tangent line states that a line in the plane of a circle that intersect the circle in exactly one point.

Common external tangent states that a common tangent that does not intersects the line segment joining the centers of circle.

Common internal tangent states that a common tangent that intersects the line segment joining the centers of circle.

Circumscribe polygon states that a polygon with all sides tangent to a circle contained within the polygon.

Therefore:

A polygon with all sides tangent to a circle contained within the polygon = Circumscribe polygon

A common tangent that intersects the line segment joining the centers of circle = Common internal tangent

A common tangent that does not intersects the line segment joining the centers of circle = Common external tangent

a line in the plane of a circle that intersect the circle in exactly one point = Tangent line

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3 years ago