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AVprozaik [17]
3 years ago
14

A total of 350 signatures is needed for a petition to be considered by the town legislature. If 125 signatures have already been

obtained, what percentage of the signatures needed must still be acquired for the petition to be considered?
Mathematics
1 answer:
zysi [14]3 years ago
3 0
<u>125</u> = .357 = about 36%<u>
</u>350<u>
</u>
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Kelly has a rock garden with a length of 6 feet. She constructs a scale model of the rock garden using the
Annette [7]

Answer:

  • (a) 3 inches

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Explanation:

(a) What is the length of the garden in her model? Show your work, including your proportion

<u>1. Scale</u>:

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<u>2. Proportion</u>:

Naming x the model length:

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Cross multiply:

  • 1 inch × 6 feet = 2 feet × x

Divide both sides by x:

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Answer: 3 inches

(b) If the width is 5 inches for the scale model and the scale is still 1 inch to 2 feet, will her scale model drawing fit on a piece of paper that is 8.5 inches by 7 inches? Why or why not?​

Both the width and the length must use the same scale, thus the corresponding sides of the scale model and the drawing must be proportional.

In the model the ratio of the length to the width is 3 inch / 5 inch

In the paper the ratio of the length to the width is 8.5 inch / 7 inch

Hence, you can see that in the model the length (mumerator of the fraction) is less than the width (denominator) while in the paper it is the opposite. Bieng the two ratios different, they are not proportional, and you conclude that her scale model drawing will not fit on a piece of paper that is 8.5 inches by 7 inches.

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A poster is to have a total area of 125 cm2. There is a margin round the edges of 6 cm at the top and 4 cm at the sides and bott
jeka57 [31]

Answer:

The correct answer is 15 cm.

Step-by-step explanation:

Let the width of the required poster be a cm.

We need to have a 6 cm margin at the top and a 4 cm margin at the bottom. Thus total margin combining top and bottom is 10 cm.

Similarly total margin combining both the sides is (4+4=) 8 cm.

So the required printing area of the poster is given by {( a-10 ) × ( a - 8) } cm^{2}

This area is equal to 125 cm^{2} as per as the given problem.

∴ (a - 10) × (a - 8) = 125

⇒ a^{2} - 18 a +80 -125 =0

⇒ a^{2} - 18 a -45 = 0

⇒ (a-15) (a-3) = 0

By law of trichotomy the possible values of a are 15 and 3.

But a=3 is absurd as a > 4.

Thus the required answer is 15 cm.

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Answer:

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