Suppose f(x)=2x−5. Find the value of f(3)

What is the relationship between area in the scale drawing and area on the on the actual tennis court if the scale is 1in.: 5ft.

sveticcg [70]

Given:

Length of the scale = 15.6 in.

Width of the scale = 7.2 in.

Scale of drawing = 1 in. : 5ft.

To find:

The ratio of area of the actual court to the area of the drawing (as a unit rate).

And to check whether it is the same as the ratio of length of the actual court to the length of the drawing.

Step-by-step explanation:

We have,

1 in. = 5ft.

Now, using this scale we get

15.6 in. = (15.6 × 5) ft =78 ft.

7.2 in. = (7.2 × 5) ft = 36 ft.

So, the actual length and width of tennis court are 78 ft and 36 ft respectively.

Area of actual tennis court is

$Area=length\times width$

$Area=78\times 36$

$Area=2808\text{ ft}^2$

The area of drawing is

$Area=15.6\times 7.2$

$Area=112.32\text{ in.}^2$

Now, ratio of area of the actual court to the area of the drawing (as a unit rate) is

$\dfrac{2808}{112.32}=\dfrac{25}{1}=25:1$

Ratio of area is 25:1 and ratio of length is 5:1 both area not same.

Therefore, the ratio of area of the actual court to the area of the drawing (as a unit rate) is 25:1.

7 0

3 years ago

A garden has an area of 286ft. It’s length is 9ft more than it’s width. What are the dimensions of the garden?

Gelneren [198K]

Answer:

13

Step-by-step explanation:

x × (x + 9) = x² + 9x = 286
x² + 9x - 286 = 0
(x - 13)(x + 22)
x = 13 or -22
Since you cannot have negative length, it’s 13

3 0

2 years ago

Help me answer these, please<br>(-6)×(-2)= <br>4×(-8)=<br>7×(-5)=

nikdorinn [45]

2 negatives make a positive.
1 negative and 1 positive make a negative.
12
32
35

8 0

3 years ago

Read 2 more answers

A - Frequency

Marina CMI [18]

Answer:

Step-by-step explanation:

When we collect a large data we may find a single entry repeated. In these cases we prepare frequency distribution with x = the item in one column and f = the no of times it repeats i.e. frequency in other column.

Similarly for class intervals also, we write as frequency to the right side of interval column which gives no of items which fall within the class.

This process ensures compact presenting of data.

Hence we have

a)The number of observations that fall in a class

answer: Frequency

b) The relative frequency of a class multiplied by 100

answer: Percentage. Because when we express probability as a percentage we get total 100

c) The ratio of the frequency of a class to the total number of observations

answer: Relative frequency

(Relative frequency also known as probability is frequency/total entries)

8 0

3 years ago

Read 2 more answers

Suppose the mean height for adult males in the U.S. is about 70 inches and the standard deviation is about 3 inches. Assume men’

nlexa [21]

Question options :

a. They should be between 64 and 76 inches tall.

b. They should be close to the height that is 95% of the mean. That is, 66.5 inches, plus or minus 2 standard deviations.

c. They should be at or below the 95th percentile, which is 74.92 inches.

d. None of the above.

Answer: a. They should be between 64 and 76 inches tall.

Step-by-step explanation:

Given the following :

Assume men's height follow a normal curve ; and :

Mean height = 70 inches

Standard deviation= 3 inches

According to the empirical rule ;

Assuming a normal distribution with x being random variables ;

About 68% of x-values lie between -1 to 1 standard deviation of the mean. With about 95% of the x values lying between - 2 and +2 standard deviation of mean. With 99.7% falling between - 3 to 3 standard deviations from the mean.

Using the empirical rule :

95% will fall between + or - 2 standard deviation of the mean.

Lower limit = - 2(3) = - 6

Upper limit = 2(3) = 6

(-6+mean) and (+6+ mean)

(-6 + 70) and (6+70)

64 and 76

8 0

3 years ago